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3 years ago

For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?

Mathematics

1 answer:

viva [34]3 years ago

8 0

Answer:

option C. $-\frac{5}{13}$

Step-by-step explanation:

we have that

The point (-5,-12) belong to the III quadrant

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

$h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units$

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

$cos(\theta)=-\frac{5}{13}$

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2 years ago

Last term of the arithmetic progression 8,15,22 is 218. Find the number of terms.

icang [17]

Answer:

31 terms.

Step-by-step explanation:

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3 years ago

Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave

natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\$

So,

$AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units$

The perimeter of triangle will be:

$P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units$

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

#LearnwithBrainly

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3 years ago

Francis earns $3.50 an hour mowing lawns. He also gets a $10.00 a week allowance. Bella earns $5.25 an hour babysitting and spen

Alika [10]

3.5h+10=5.25h-11
21=1.75h
12=h

3.5(12)+10=5.25(12)-11
52=52

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3 years ago

C(1, 6) ; y=4x+1 Put answer in slope intercept form

alina1380 [7]

Answer:

slope intercept form is y=mx+b

your m is 4

all you do is plug the numbers in

y=4x+6

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3 years ago