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Arte-miy333 [17]

3 years ago

6

For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?

1 answer:

viva [34]3 years ago

8 0

Answer:

option C. $-\frac{5}{13}$

Step-by-step explanation:

we have that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

$h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units$

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

$cos(\theta)=-\frac{5}{13}$

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a vase has 6 flowers in it. there are 3 roses, 1/3 are peonies, and the rest are lilies. what fraction of the flowers are lilies

Rudik [331]

Hi there!

We can start off by taking out some key information from this problem.

- 6 flowers in the vase.
- 3 are roses. (3/6)
- 2 are peonies. (2/6)
- 1 is a Lily. (1/6)

By converting all of the flowers to have a common denominator we can clearly see that 1/6 of the flowers are lilies.

4 0

2 years ago

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horsena [70]

Answer:

-15a+d

Step-by-step explanation:

5a-20a+12d-11d

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3 0

3 years ago

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mario62 [17]

Answer:

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Step-by-step explanation:

What you can do is use the first two coordinates. This would get the formula to look like this:

$\frac{4 - 2}{6 - 3}$

From here you get ⅔ for the slope.

4 0

2 years ago

What is 4 1/2 pint to quart?

Ivanshal [37]

There are two pints every quarter.

So let's convert pints to quarter

$\frac{4\frac{1}{2} }{2} =\frac{\frac{9}{2} }{2} = \frac{9}{4}$

There 4 1/2 pint is to 9/4 quarter.

Hope that helps!

p.s. look at my diagram to help you remember

5 0

1 year ago

Suppose you know that Mr. and Mrs. Vincent have at most eight children. One day you happen to meet two girls who were the Vincen

lianna [129]

Answer:

The number of children are 4 out of which 3 are girls

Step-by-step explanation:

Data provided in the question:

P(Two randomly selected children are girls) = $\frac{1}{2}$

now,

let the number of children be 'n'

the number of girls be 'x'

thus,

P(Two randomly selected children are girls) = $\frac{^xC_2}{^nC_2}$ = $\frac{1}{2}$

also,

$^nC_r$ = $\frac{n!r!}{(n-r)!}$

thus,

$\frac{\frac{x!2!}{(x-2)!}}{\frac{n!2!}{(n-2)!}}$ = $\frac{1}{2}$

or

$\frac{x(x-1)}{n(n-1)}$ = $\frac{1}{2}$

or

2x(x-1) = n(n-1)

now

for x = 3 and n = 4

i.e

2(3)(3-1) = 4(4-1)

12 = 12

hence, the relation is justified

therefore,

The number of children are 4 out of which 3 are girls

3 0

3 years ago