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olga55 [171]
2 years ago
14

A charity received 240 donations. The total amount received was 7,680. If x represents the average donation, which THREE stateme

nts are
correct?
Mathematics
1 answer:
ch4aika [34]2 years ago
6 0

Answer:

x=32

Step-by-step explanation:

You might be interested in
The radius of a semicircle is 4 miles. What is the semicircle's area?
adell [148]

Answer:

8\pi miles or 25.133 miles

Step-by-step explanation:

your radius is 4 miles.

The area of a circle is A= \pi r^{2}

Therefore, the area of this circle is 4^{2} \pi, or 16\pi

Half of this area, because what you're looking for is a semi-circle, is:

8\pi (exact) or 25.133 (rounded) miles.

6 0
2 years ago
What is the 100 nearest 513
ololo11 [35]

Answer: 500

Step-by-step explanation:

it is closest and is under 550. if it were 551 through 599 it would be 600

6 0
4 years ago
In 25 words or fewer, is this solution reasonable? Why or why not?
Julli [10]

Step-by-step explanation:

This solution is reasonable because equal slopes are parallel and negative reciprocals are perpendicular. Four right angles make up a rectangle, and this fulfills it

7 0
3 years ago
The table below shows the transportation method of all of the employees who work at the mall. What percent of employees walk to
Pepsi [2]

Answer:

0.005 or 0.5% walk

Step-by-step explanation:

Total:

758 + 530 + 7 + 105 = 1400

To find how many employees walk:

7/1400 = 0.005

6 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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