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2 years ago

HELP ME DO THIS PLEASE IM STRESSING OUT

Mathematics

2 answers:

faltersainse [42]2 years ago

7 0

The answer is 36!!!!

riadik2000 [5.3K]2 years ago

4 0

Answer:

Step-by-step explanation:

ik it bc im smart

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Help due in 45 minutes!!

Nat2105 [25]

Answer:

(14,-1)

Step-by-step explanation:

okay so first you need to use the "x=4y+10" in the first equation.

Rewrite as

3(4y+10) +11y=7

Distribute the 3(4y+10)

Rewrite as

12y+30

You'll have the equation

12y +30 +11y= 7

Subtract the 7 from both sides

12y+30+11y-7= 0

Combine like terms

23y+23=0

the best thing to do here is divide the equation by 23.

23/23 = 1

you'll have

y + 1 = 0

this simplifies to

y= -1

use this y value to solve for x

the easiest way to do this is start with the equation

x = 4y +10

Substitute the y for -1

x = -4(-1) +10

x = 4 +10

x = 14

the solution point is

(14,-1)

3 0

2 years ago

At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g

Tresset [83]

Answer:

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n( $S \cup A\cup G$ ) = 100

n( $S \cap A\cap G$ ) = 9

n( $S \cap A$ ) = 20

n( $A \cap G$ ) = 35

n( $G \cap S$ ) = 29

Formula:

n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n( $G \cap S$ ) - n( $A \cap G$ ) + n( $S \cap A\cap G$ )

= 72 - 35 - 29 + 9

= <em>17</em>

6 0

2 years ago

X2 - x - 42 <br>a=? <br>b=? <br>C=? <br><br><br><br>help me

lisabon 2012 [21]

Step-by-step explanation:

thr standard form for a quadratic equation is:

ax²+bx+c

in this example, a=1, b=(-1), c=(-42)

6 0

1 year ago

Part A

kap26 [50]

Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1

<h3>How to reflect the polygon?</h3>

The coordinates are given as:

F(2, – 1), G(5,2), H(8, 3), and I(6, 0)

The line of reflection is given as:

y = -1

To reflect the line, we apply the following rule of reflection

(x,y) $\to$ (x,-y-2)

So, we have the following coordinates of the image

F' = (2, – 1)

G' = (5,-4)

H' = (8, -5)

I' = (6, -2)

See attachment for the image of the reflected polygon