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nata0808 [166]
3 years ago
15

The lengths of pregnancies are normally distributed with a mean of 264 days and a standard deviation of 15 days. if 36 women are

randomly selected, find the probability that they have a mean pregnancy between 264 days and 266 days.
Mathematics
1 answer:
Nitella [24]3 years ago
5 0
Given that a sample of 36 women is selected, the probability that the mean is between 264 days and 266 days will be found as follows:
the std deviation of the sample will be:
σ/√n
plugging the values we obtain:
15/√36
=15/6
=2.5
hence the z-score when x=264 will be:
z=(264-264)/2.5
z=0
thus:
P(x<264)=P(z<0)=0.5

the z-score when x=266 will be:
z=(266-264)/2.5
z=0.8
hence
P(x<266)=P(z<0.8)=0.7881
thus
P(264<x<266)=P(0.5<z<0.7881)
=0.7881-0.5
=0.2881

Answer: 0.2881
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As given, the variance of a variable is 169, hence its standard deviation will be,

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Answer

1

LammettHash

Genius

8K answers

42M people helped

Standard deviation is the square root of variance, so the std dev is .

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1

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