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2 years ago

Plz plz help my maths paper

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

3 0

Answer:

(c)

Step-by-step explanation:

Answer is (c) 2

Its my guess

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Solve for X 1/2(10X-8)=1/3(21-15X

Tasya [4]

The answer would be x=11/10

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4 years ago

Find the value of the second term in this sequence. 34,___ , 84, 109, 134

STALIN [3.7K]

The answer is 59
Because in the sequence you add 25 the the next number for example 34+25=59 then 84+25=109 and 109+25=134

6 0

4 years ago

HELP MEEEE PLEASEEEEEEEEEEEEEE

Agata [3.3K]

Answer:

a = 4

Step-by-step explanation:

a^2 + b^2 = c^2

a= ?

b= 3

c= 5 (c is always the hypotenuse)

*plug in given values

a^2 + 3^2 = 5^2

a^2 + 9 = 25

-9 -9

a^2 = 16

*find the square root

sqrt(a) = sqrt(16)

a = 4

8 0

3 years ago

Read 2 more answers

For the function f x equals square root x ^ 3 - x, State the condition that must be satisfied for the FX to be Define. Then, sol

Svetradugi [14.3K]

Answer:

Domain: $[-1,0]\cup [1,\infty )$

Step-by-step explanation:

Since we know that a square root function is not defined for negative numbers. In order our function to be defined values inside radical must be greater than or equal to zero.

Our function will be defined when $x^{3} -x\geq 0$

$x(x^{2} -1)\geq 0$

$x(x-1)(x+1)\geq 0$

$1\geq x\leq 0$ or $x\geq1$

Now we will use number line method of solving inequalities to check whether our answer is right or not.

Let us try -2, -1/2, 1/2 and 2 to check which conditions meet our criteria.

$-2^{3} --2\geq 0\\-6\leq 0$

$(\frac{-1 }{2}) ^{3} -(\frac{-1}{2}) \geq0$

$\frac{-1}{8} +\frac{1}{2} \geq 0\\\frac{3}{8} \geq 0$

$(\frac{1 }{2}) ^{3} -\frac{1}{2} \geq0$

$\frac{1}{8} -\frac{4}{8} \leq 0$

$2^{3} -2\geq 0\\6\geq 0$

Therefore, we can see that our function is defined when $1\geq x\leq 0$ or $x\geq1$ and domain of f(x) is $[-1,0]\cup [1,\infty )$ .

4 0

3 years ago

What is the value of the expression 2/5 + 3/7

podryga [215]

Answer: its 29/35 value....

7 0

2 years ago

Plz plz help my maths paper ​

Plz plz help my maths paper