Answer:
B, C and F
Step-by-step explanation:
Given
f(x) = ![\frac{7}{2x(x+3)(x-9)}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B2x%28x%2B3%29%28x-9%29%7D)
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
solve
2x(x + 3)(x - 9) = 0
Equate each factor to zero and solve for x
2x = 0 ⇒ x = 0 → C
x + 3 = 0 ⇒ x = - 3 → B
x - 9 = 0 ⇒ x = 9 → F
Answer:
a) True
b) False
c) False
d) True
e)False
Step-by-step explanation:
a) True because Since it is non-empty and it is bounded maximum of A is an upper bound and hence contains supremum
b) False because Suppose A to be the interval (0,1) and L= 1. Then clearly supA= 1 < 1 = L
c) False because Let A= (0,1) and B = {1} it shows that Sup A =1 = Inf B
d)True
e)False because lets Take for both A and B the interval (0,1). it is easy to see that supA ≤ supB, but no element of B is an upper bound for A.
Answer:16.66
Step-by-step explanation:
Answer:
![-8](https://tex.z-dn.net/?f=-8)
Step-by-step explanation:
![14-\frac{110}{5}=\frac{14*5-110}{5}=\frac{70-110}{5}=\frac{-40}{5}=-8](https://tex.z-dn.net/?f=14-%5Cfrac%7B110%7D%7B5%7D%3D%5Cfrac%7B14%2A5-110%7D%7B5%7D%3D%5Cfrac%7B70-110%7D%7B5%7D%3D%5Cfrac%7B-40%7D%7B5%7D%3D-8)