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Radda [10]
2 years ago
8

Find the equation of the exponential function represented by the table below:

Mathematics
1 answer:
shusha [124]2 years ago
8 0

Answer:

6.4

Step-by-step explanation:

i did a test on it and figerd out that the answer is 6.4

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van gogh

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What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?<br> –10<br> –9<br> –8<br> –7
Dominik [7]
Hello,

4x-12<=16+8x==> -28<=4x==>x>=-7

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Answer D
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Find an equation in standard form for the hyperbola with vertices at (0,plus or minus 6) and asymptotes at y= (plus or minus 3/5
antoniya [11.8K]

Answer:

\frac{(y)^2}{36}-\frac{(x)^2}{100}=1

Step-by-step explanation:

Given:

Vertices of Hyperbola : (0 ± 6) or (0,6) and (0,-6)

and asymptotes at y= (±3/5)x 0r y= 3/5 x and y=-3/5 x

The vertices are of vertical hyperbola. The equation used will be:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\\

The Center of hyperbola (h,k) =(0,0)

The Distance from vertices to center is a and a = 6 (given)

For equation we have value of h,k and a and need to find value of b

we know,

y= k ± a/b (x-h)

Values of h and k are zero

y= 0 ± a/b (x-0)

y= (± a/b ) x

We are given asymtotes at y= (± 3/5)x which is equal to y= (± a/b ) x

as a = 6 then b= 10 i.e The simplified form of 6/10 is 3/5 so value of b=10

Putting values of a,b,h and k in equation we get,

\frac{(y-0)^2}{(6)^2}-\frac{(x-0)^2}{(10)^2}=1\\\\\frac{(y)^2}{36}-\frac{(x)^2}{100}=1

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4 years ago
Which pairs of expressions are equivalent <br><br> More the 1 answer
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The first 3 pairs of expressions are equivalent.

Step-by-step explanation:

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3 years ago
What is the volume of the cylinder?
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150 if I'm not wrong
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3 years ago
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