Answer:
Va / Vb = 0.5934
Explanation:
First step is to determine total head losses at each pipe
at Pipe A
For 1/4 open gate valve head loss = 17 *Va^2 / 2g
elbow loss = 0.75 Va^2 / 2g
at Pipe B
For 1/3 closed ball valve head loss = 5.5 *Vb^2 / 2g
elbow loss = 0.75 * Vb^2 / 2g
Given that both pipes are parallel
17 *Va^2/2g + 0.75*Va^2 / 2g = 5.5 *Vb^2 / 2g + 0.75 * Vb^2 / 2g
∴ Va / Vb = 0.5934
Answer:
See below
Explanation:
<u>Check One-Sample T-Interval Conditions</u>
Random Sample? √
Sample Size ≥30? √
Independent? √
Population Standard Deviation Unknown? √
<u>One-Sample T-Interval Information</u>
- Formula -->

- Sample Mean -->

- Critical Value -->
(given
degrees of freedom at a 95% confidence level) - Sample Size -->

- Sample Standard Deviation -->

<u>Problem 1</u>
The critical t-value, as mentioned previously, would be
, making the 95% confidence interval equal to 
This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.
I would help if It wasn’t so confusing.
Answer:
note:
<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>
Answer:
Explanation:
Total weight being moved = 5000+1000+200
= 6200 lb .
Force applied = 700 lb
= 700 x 32 = 22400 poundal .
acceleration (a) = 22400 / 6200
= 3.613 ft /s²
To know velocity after 6 ft we apply the formula
v² = u² + 2as
v² = 0 + 2 x 3.613 x 6
43.356
v = 6.58 ft/s