The organic acid, ACOOH, reacts reversibly with the alcohol BOH, to form the ester ACOOB according to the stoichiometric equatio
n: ACOOH BOH ACOOB H20 The reaction will be carried out in an ideal batch reactor and the water will be removed rapidly by stripping with an inert gas as the reaction proceeds. Therefore, the reverse reaction can be neglected. The rate equation for the forward reaction is: The value of the rate constant s k = 0.16 M-2h-1 at 373 K. The reaction is carried out in solution in a 2000 L reactor. The initial concentration of ACOOH is ACOOHJo = 2 M and the initial concentration of BOH is [BOHo 3 M. The reactor is operated isothermally at 373 K. How long must the liquid phase reaction run in an ideal, isothermal batch reactor to obtain a fractional conversion of A of 0.9?
1 answer:
You might be interested in
Answer:
The given grammar is :
S = T V ;
V = C X
X = , V | ε
T = float | double
C = z | w
1.
Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.
From the given grammar,
Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.
No other variables generate variable X or ε.
So, only variable X is nullable.
2.
First of nullable variable X is First (X ) = , and ε (epsilon).
L.H.S.
The first of other varibles are :
First (S) = {float, double }
First (T) = {float, double }
First (V) = {z, w}
First (C) = {z, w}
R.H.S.
First (T V ; ) = {float, double }
First ( C X ) = {z, w}
First (, V) = ,
First ( ε ) = ε
First (float) = float
First (double) = double
First (z) = z
First (w) = w
3.
Follow of nullable variable X is Follow (V).
Follow (S) = $
Follow (T) = {z, w}
Follow (V) = ;
Follow (X) = Follow (V) = ;
Follow (C) = , and ;
Explanation:
