Answer:
2 yes ot will 2 would be a yes but i dont know how i would put that into a paragraph
Explanation:
There are two ways to find out the equivalent impulse response of the system.
1. Convolution in time domain
2. Simple multiplication in Laplace domain
2nd method is efficient, easy and is less time consuming.
Step 1: Take the Laplace transform of the given three impulse response functions to convert time domain signals into s-domain
Step 2: Once we get signals in s-domain, multiply them algebraically to get the equivalent s-domain response.
Step 3: Take inverse Laplace transform of the equivalent impulse response to convert from s-domain into time domain.
Solution using Matlab:
Step 1: Take Laplace Transform
Ys1 = 1/(s + 1)
Ys2 = 1/s - exp(-s/2)/s
Ys3 = exp(-3*s)
Step 2: Multiplication in s-domain
Y = (exp(-(7*s)/2)*(exp(s/2) - 1))/(s*(s + 1))
Step 3: Inverse Laplace Transform (Final Solution in Time Domain)
h = heaviside(t - 7/2)*(exp(7/2 - t) - 1) - heaviside(t - 3)*(exp(3 - t) - 1)
Answer
1056
Explanation:
for example
A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate
Quantity of soil to be excavated from pit in m3
Answer:
Heat required =7126.58 Btu.
Explanation:
Given that
Mass m=20 lb
We know that
1 lb =0.45 kg
So 20 lb=9 kg
m=9 kg
Ice at -15° F and we have to covert it at 200° F.
First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.
We know that
Specific heat for ice
Latent heat for ice H=336 KJ/kg
Specific heat for ice
We know that sensible heat given as
Heat for -15F to 32 F:
Q=858.69 KJ
Heat for 32 Fto 200 F:
Q=6330.74 KJ
Total heat=858.69 + 336 +6330.74 KJ
Total heat=7525.43 KJ
We know that 1 KJ=0.947 Btu
So 7525.43 KJ=7126.58 Btu
So heat required to covert ice into water is 7126.58 Btu.
Answer:
how many people were asked though
Explanation: