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wolverine [178]
3 years ago
11

A seamless pipe 800mm diameter contains a fluid under a pressure of 2N/mm2. If the permissible tensile stress is 100N/mm2, find

the minimum thickness of the pipe.
Engineering
1 answer:
Bad White [126]3 years ago
3 0

Answer:

8 mm

Explanation:

Given:

Diameter, D = 800 mm

Pressure, P = 2 N/mm²

Permissible tensile stress, σ = 100 N/mm²

Now,

for the pipes, we have the relation as:

\sigma=\frac{\textup{PD}}{\textup{2t}}

where, t is the thickness

on substituting the respective values, we get

100=\frac{\textup{2\times800}}{\textup{2t}}

or

t = 8 mm

Hence, the minimum thickness of pipe is 8 mm

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Solution :

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$T_{sat}=87.745^\circ  F$

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For pressure, P = 20 psia

$h_{2f} = 11.445 \ Btu/lbm$

$h_{2g} = 102.73 \ Btu/lbm$

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Change in temperature, $\Delta T = T_2-T_1$

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Now we find the quality,

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$x_2=0.32198$

The final energy,

$u_2=u_f+x_2.u_{fg}$

   $=11.401+0.32198(82.898)$

   $=38.09297 \ Btu/lbm$

Change in internal energy  

$\Delta u= u_2-u_1$

   = 38.09297-40.5485

  = -2.4556        

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Answer:

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Explanation:

Given:

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7 0
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Experimental Design Application Production engineers wish to find the optimal process for etching circuit boards quickly. They c
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Answer:

Hello your question is incomplete attached below is the missing part and answer

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Effect A

Effect B

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Effect AB

Effect AC

Effect AD

Effect BC

Effect BD

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Answer :

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C  = Non-significant

D  = Non-significant

AB  = Non-significant

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