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wolverine [178]
3 years ago
11

A seamless pipe 800mm diameter contains a fluid under a pressure of 2N/mm2. If the permissible tensile stress is 100N/mm2, find

the minimum thickness of the pipe.
Engineering
1 answer:
Bad White [126]3 years ago
3 0

Answer:

8 mm

Explanation:

Given:

Diameter, D = 800 mm

Pressure, P = 2 N/mm²

Permissible tensile stress, σ = 100 N/mm²

Now,

for the pipes, we have the relation as:

\sigma=\frac{\textup{PD}}{\textup{2t}}

where, t is the thickness

on substituting the respective values, we get

100=\frac{\textup{2\times800}}{\textup{2t}}

or

t = 8 mm

Hence, the minimum thickness of pipe is 8 mm

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Dimensional analysis: a)-Can be used to derive equations and non-dimensional numbers. b)-Helps in planning experiments. c)-Is an
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Answer:

Option e)

Explanation:

Dimensional Analysis helps in the analysis of relationship between physical quantities, checking its dimension thus checking the accuracy of a given or to find the dimensions of a quantity or the degree of correctness of an equation.

Dimensional analysis has some of the applications that are listed below:

  • To establish a relationship between physical quantities
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3 years ago
Consider a hot working operation in which there is no work hardening, but the flow stress is sensitive to the strain rate. Calcu
alexandr402 [8]

Explanation:

You can use Hollomon's equation to estimate this.

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A 12-kN tensile load will be applied to a 50-m length of steel wire with E = 200 GPa. Determine the smallest diameter wire that
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Answer:

The smallest wire diameter that can be used is 1 cm

Explanation:

First, we find the smallest diameter using the criterion of maximum normal stress:

Max. Stress = 150 x 10^6 Pa = F/A

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d² = (12000 N)(4)/(150 x 10^6 Pa)(π)

d = √1.0185 x 10^-4 m²

d = 0.010 m = 1 cm

Now, we find the smallest diameter using the criterion of maximum strain:

Max. Strain = Max. Change in Length/Original Length = 0.025 m/50 m

Max. Strain = 5 x 10^-4 mm/mm

Now,

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using values:

5 x 10^-4 mm/mm = (12000 N)/(200 x 10^9 Pa)(πd²/4)

d =√(12000 N)(4)/(5 x 0^-4)(200 x 10^9 Pa)(π)

d = 0.012 m = 1.2 cm

Now, by comparison in both cases it can be noted that the smallest value of the diameter is <u>1 cm</u>, which is limited by maximum stress.

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3 years ago
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Answer:

[012]  :

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[721] :      

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[110]  :

Here z component is zero.

That is why this is  in x -y plane

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