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schepotkina [342]
3 years ago
15

Calculate the availability of a system where the mean time between failures is 900 hours and the mean time to repair is 100 hour

s.
Engineering
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

The availability of system will be 0.9

Explanation:

We have given mean time of failure = 900 hours

Mean time [to repair = 100 hour

We have to find availability of system

Availability of system is given by  \frac{mean\time\ of\ failure}{mean\ time\ of\ failure+mean\ time\ to\ repair}

So availability of system =\frac{900}{900+100}=\frac{900}{1000}=0.9

So the availability of system will be 0.9

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Answer:

Hello your question is incomplete attached below is the complete question

Answer : Factor of safety for point A :

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ii) using DE

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(Fos)MSS =  3.04

ii) using DE

(Fos)DE = 3.604

Explanation:

Factor of safety for point A :

i) using MSS

(Fos)MSS =  3.22

ii) using DE

(Fos)DE = 3.27

Factor of safety for point B

i) using MSS

(Fos)MSS =  3.04

ii) using DE

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Attached below is the detailed solution

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Explanation:

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solution

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