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3 years ago

~PLEASE HELP ASAP OFFERING 25 POINTS ASAP PLEASE ANSWER ALL QUESTIONS~

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

6. If 55% of the selling price is markup, the remainder (45%) is the cost. Gaitan can pay up to 45% of 489.50 = $220.28.

7. If 52% of the selling price is markup, the remainder (48%) is the cost. 48% of the selling price is $38.87.

... 0.48 × selling price = cost

... selling price = cost/0.48 = $38.87/0.48 = $80.98

8. If 40% of the selling price is markup, the remainder (60%) is the cost, $12.95.

... 0.60 × selling price = $12.95

... selling price = $12.95/0.60 = $21.58

9. If 35% of the selling price is markup, the remainder (65%) is the cost.

... 0.65 × $24.00/dz = $15.60/dz

10. If 60% of the selling price is markup, the remainder (40%) is the cost. Veronica can pay up to 40% of $600.00 = $240 for the jacket.

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Ivan has 15 yards of green felt and 12 yards of blue felt to make 3 quilts if Ivan uses the same total number of yards for each

mixas84 [53]

Answer:

9 yards

Step-by-step explanation:

Let the length of each quilt be 'l'.

Given:

Length of green felt (g) = 15 yards

Length of blue felt (b) = 12 yards

Total number of quilts = 3

Now, the length of 3 quilts is given as:

$Total\ length=l+l+l=3l$ ----- (1)

As per question:

Total length = Length of green felt + Length of blue felt

Total length = $g+b$

$Total\ length=15+12=27$ --------- (2)

Now, comparing equations (1) and (2), we get:

$3l=27\\\\l=\frac{27}{3}\\\\l=9\ yards$

Hence, each quilt measures 9 yards in length.

3 0

3 years ago

How to write three hundred thousand, five thousand sixty three in standard form

anygoal [31]

300,000 <-- three hundred thousand

5,000 <-- five thousand

63 <-- sixty three

300,000
5,000
63

305,063

305,063 is your answer.

Hope this helps.

3 0

3 years ago

Read 2 more answers

I need help with Mondays homework please someone help

boyakko [2]

Left column. Right column
6m. 6x10^0m
120,000m. 12x10^4m OR 1.2x10^5m
0.0012m. 12×10^4m OR 1.2×10^-3m
300m. 3×10^2m
0.6m. 6x10^-1m
0.0009m 9x10^-4m
6000m. 6x10^3m

3 0

3 years ago

the hoover dam is 725 feet tall. how long would it take an object to fall from the top to the base of the dam? round the answer

Alinara [238K]

Answer:

45.05 seconds

Step-by-step explanation:

Use the formula: d = v $i$ t + $\frac{1}{2}$ a $t^{2}$

d = distance v $i$ = initial velocity (m/s)

t = time (s) a = acceleration (m/ $s^{2}$ )

m is meters and s is seconds. They are units of measurement so leave them be.

Assuming the object is simply dropped, the initial velocity is 0 since the object was not moving before it was dropped.

The distance is 725 feet, which is 220.98 meters.

The acceleration is 9.81m/ $s^{2}$ since that is the acceleration of Earth's gravity, aka free fall.

Time is what we are trying to find so just leave it as the variable t.

So plug the values into the equation:

220.98m = (0)(t) + $\frac{1}{2}$ (9.81m/ $s^{2}$ )(t)

220.98m = (4.905m/ $s^{2}$ )(t)

45.0519877676s = t

t = 45.05s

Remember to pay attention to units because your answer will be wrong otherwise

7 0

2 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

6 0

3 years ago