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3 years ago

point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form

Mathematics

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

$4\sqrt{10}$

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of point A and point B in distance formula we will get,

$\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}$

$\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}$

$\text{Distance between point A and point B}=\sqrt{16+144}$

$\text{Distance between point A and point B}=\sqrt{160}$

$\text{Distance between point A and point B}=4\sqrt{10}$

Therefore, the length of segment AB is $4\sqrt{10}$ .

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Refer to the attachment for the graph as well .

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