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Arisa [49]
2 years ago
13

Two forces of 494 newtons and 590 newtons act on a point. The resultant force is 1079 newtons. Find the angle between the two fo

rces.
Mathematics
1 answer:
Sonbull [250]2 years ago
4 0

Answer:

Use Law of Cosines

Step-by-step explanation:

1079²= 590² + 494²- (2)(590)(494) cos θ.

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Tell whether a triangle can have sides with the
Dmitry [639]

Answer:

3x+2 \ne x^2 \ne 2x for x = 4

Step-by-step explanation:

Given

Shape: Triangle

Dimension: 3x + 2, x^2 and 2x

x = 4

Required

Determine if it has equal sides

To do this, we simply substitute 4 for x in the given dimensions

<u>3x + 2</u>

3x + 2 = 3 * 4 + 2

3x + 2 = 12 + 2

3x + 2 = 14

<u>x^2 </u>

x^2 = 4^2

x^2 = 16

<u>2x</u>

<u></u>2x = 2 * 4<u></u>

2x = 8

3x+2 \ne x^2 \ne 2x for x = 4

8 0
3 years ago
What is a mutual fund’s
leonid [27]

A pool of money where investors buy shares and a fund manager invests them and gives the investor the return; the way that most Americans invest their money because of the ease. hope that helps!

3 0
3 years ago
Please help and I will give brainliest if u do.
kirill115 [55]

Answer:

See explanation below

Step-by-step explanation:

The width is 4 inches

So, the area of the base is 20 inches squared

The height is 4 inches

So, the volume of the prism is 80 inches cubed

3 0
3 years ago
Read 2 more answers
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
») What is the volume of a ball with adiameter of 6 centimeters? Use 3.14for (pie)How is the volume of a sphere related tothe vo
Dahasolnce [82]
Volume of a sphere and a cone

We have that the equation of the volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

We have that the radius of a sphere is half the diameter of it:

Then, the radius of this sphere is

r = 6cm/2 = 3cm

<h2>Finding the volume of a sphere</h2>

We replace r by 3 in the equation:

\begin{gathered} V=\frac{4}{3}\pi r^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot3^3 \end{gathered}

Since 3³ = 3 · 3 · 3 = 27

\begin{gathered} V=\frac{4}{3}\pi3^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot27 \end{gathered}

If we use π = 3.14:

\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=\frac{4}{3}\cdot3.14\cdot27 \\ \downarrow \\ V=4.18\bar{6}\cdot27 \end{gathered}

Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:

4.18666... ≅ 4.19

Then, we have that:

\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=4.19\cdot27 \\ =113.13 \end{gathered}

Then, we have that:

<h2>Finding the volume of a cone</h2>

We have that the volume of a cone is given by:

V=\frac{1}{3}\pi r^2h

where r is the radius of its base and h is the height:

Then, in this case

r = 3

h = 6

and

π = 3.14

Replacing in the equation for the volume:

\begin{gathered} V=\frac{1}{3}\pi r^2h \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \end{gathered}

Then, we have:

3² = 9

\begin{gathered} V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot9\cdot6 \\ V=\frac{1}{3}\cdot3.14\cdot54 \\ V=56.52 \\  \end{gathered}

Answer: the volume of the cone that has the same circular base and height is 56.52 cm³

5 0
1 year ago
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