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Alisiya [41]
3 years ago
8

How do i get y alone when 3(–1)+5y=17

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0
3(-1) + 5y = 17
add 3 to both sides
5y=20
divide by 5
y=4

Temka [501]3 years ago
4 0
Multiple 3(-1) and get 3 subtract that from 17 which is 14 divide by 5 to make y alone the answer is 14/5
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Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

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c_n = b_{n+1} - b_n

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b_{n+1} = b_n + 2

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and so on down to

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We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

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and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

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Hello!

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