Answer: Yes these triangles are similar
Step-by-step explanation:
First lets write down what we know just to make life easier
x=9
TL should be similar to CH
LY should be similar to KH
The angles should be equal due to SAS
So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14
So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14
Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5
Hope this helps.
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall
or 20(x+5) if you wish.
Answer:
It will take 100 songs for the monthly price of Napster to cost the same as iTunes.
Step-by-step explanation:
Let's create two equations to represent iTunes (T(d)) and Napster (N(d)):
T(d)=0.99d
N(d)=0.89d+10
In order for us to find when the two prices will be the same, let's set the equations equal to each other and solve for x:
0.99d=0.89d+10
0.1d=10
d=100
Answer:
B
Step-by-step explanation:
The second one!!!
A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.
