After 25 days, it remains radon 5.9x10^5 atoms.
Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.
N(Ra) = 5.7×10^7; initial number of radon atoms
t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days
n = 25 days / 3.8 days
n = 6.58; number of half-lifes of radon
N1(Ra) = N(Ra) x (1/2)^n
N1(Ra) = 5.7×10^7 x (1/2)^6.58
N1(Ra) = 5.9x10^5; number of radon atoms after 25 days
The half-life is independent of initial concentration (size of the sample).
More about half-life: brainly.com/question/1160651
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A. Water can dissolve a wide variety of substances
Arrow on the table below draw an
Answer:
1. The balanced equation is given below:
C4H6O3 + H2O → 2C2H4O2
The coefficients are: 1, 1, 2
Explanation:
C4H6O3 + H2O → C2H4O2
The above equation can be balanced as follow:
There are 4 atoms of C on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of C2H4 O2 as shown below:
C4H6O3 + H2O → 2C2H4O2
Now, the equation is balanced as the number of atoms of the different elements present on both sides of the equation are equal.
The coefficients are: 1, 1, 2
Answer:
The answer to your question is:
Explanation:
Iron (III) ⇒ Iron (II)
Fe⁺³ + 1e⁻ ⇒ Fe⁺²
