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andrew11 [14]
3 years ago
13

Which of the following is a chemical property of a base?

Chemistry
2 answers:
lapo4ka [179]3 years ago
5 0
Answer:

D) forms hydronium ions in water

Explanation:

Answer A is an example of texture and answer B is an example of conductivity while answer C is not referring to a chemical property at all. Therefore, D would be the correct answer.
juin [17]3 years ago
4 0

Answer:

D) forms hydronium ions in water

Explanation:

Texture and conductivity are physical properties which makes answer A and B wrong. Answer C does not refer to a chemical reaction.

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Calculate the density of sulfuric acid if 35.4 mL of the acid weighs 65.14 g
Nadya [2.5K]
M/V=D
65.14/35.4≈1.84
The density of the sulfuric acid would be about 1.84g/mL
5 0
3 years ago
How much force is needed to accelerate a 66 kg skier at 2 m/sec2
alexgriva [62]

Answer:

132N

Explanation:

F=ma

F=66×2

F=132N

7 0
3 years ago
Which of the following has a mass of 10.0 g?
Serjik [45]

Answer:

a.  0.119mol Kr

Explanation:

To solve this problem, we must understand that;

     Mass  = number of moles x molar mass

Molar mass of Kr  = 83.3g/mol

                        Ar = 40g/mol

                        He = 4g/mol

                        Ne = 20.18g/mol

a0.119 mol Kr               mass  = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar             mass  = 0.4 x 40  = 16g

C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

5 0
3 years ago
POV: You buy a composite cup at the store. Explain the reason for your decision.
Len [333]

Answer:

i bought it cuz i need a cup?

Explanation:

7 0
3 years ago
Read 2 more answers
How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14
Taya2010 [7]
<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

  • Remaining mass of C-14 in a bone is 0.3125 g
  • Original mass of C-14 on the bone is 80.0 g
  • Half life of C-14 is 5370 years

We are required to determine the age of the bone;

  • Using the formula;
  • Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

  • Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

   = 8

  • Therefore, the number of half lives is 8
  • But, 1 half life is 5370 years
  • Therefore;

Age of the rock = 5370 years × 8

                          = 42960 years

Thus, the bone is 42960 years old

7 0
3 years ago
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