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Oxana [17]
3 years ago
10

What is the mole-to-mole ratio between N2 and H2?

Chemistry
1 answer:
spin [16.1K]3 years ago
5 0
Remember, look at the coefficients in the balanced equation! Here are three mole ratios:
1 mole<span> N2 / </span>3 moles<span> H2.</span>
3 moles<span> H2 / 2 moles NH3.
</span>


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What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write
LuckyWell [14K]

The balanced chemical equation for reaction of AgNO_{3} and Na_{2}SO_{4} is as follows:

2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}

From the balanced chemical equation, 2 mol of AgNO_{3} reacts with 1 mol of  NaNO_{3}.

First calculating number of moles of NaNO_{3} as follows:

M=\frac{n}{V}

On rearranging,

n=M\times V

Here, M is molarity and V is volume. The molarity of NaNO_{3}  is given 0.274 M or mol/L and volume 155 mL, putting the values,

n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol

Since, 1 mol of NaNO_{3}  reacts with 2 mol of  AgNO_{3} thus, number of moles of  AgNO_{3}  will be 2\times 0.04247 mol=0.08494 mol.

Now, molarity of  AgNO_{3} is given 0.305 M or mol/L thus, volume can be calculated as follows:

V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL

Therefore, volume of  AgNO_{3} is 278.5 mL.

4 0
3 years ago
Which to which! Ahhhh.
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Answer:

1.a

2. b

Explanation:

Distillation is a process whereby a mixture of liquids having different vapor pressures is separated into its components. At first one might think that this would be quite simple: if you have a solution consisting of liquid A that boils at 50°C and liquid B with a boiling point of 90°C, all that would be necessary would be to heat the mixture to some temperature between these two values; this would boil off all the A (whose vapor could then be condensed back into pure liquid A), leaving pure liquid B in the pot. But that overlooks that fact that these liquids will have substantial vapor pressures at all temperatures, not only at their boiling points.

source: https://chem.libretexts.org/Bookshelves/General_Chemistry/Book%3A_Chem1_(Lower)/08%3A_Solutions/8.09%3A_Distillation

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