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3 years ago

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Elements that do not have full outer electron shells will donate, share, or take from other atoms. Choose the items that have th

e correct binary ionic formula. (brainliest)

1 answer:

Gnesinka [82]3 years ago

7 0

Answer:

Ok...

Answer: YTH/JYG

Explanation:

AI+ZN+H=YTH

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What is the process by which sand dunes occur?

Arte-miy333 [17]

B............................................................................

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3 years ago

How many are molecules ( or formula) in each sample?

andre [41]

Answer:

$4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$
$16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

<u>Explanation</u>:

<u>Number of molecules for $55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$ </u>

$\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:$

Atomic mass of Na + H + C + 3(O) = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

$\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }$

$55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)$

$=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

<u>Number of molecules for for $\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$ </u>

$\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

$459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.$

$=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

8 0

3 years ago

How many grams of Sodium will have the same number of atoms as 6 grams of Magnesium?

Ksivusya [100]

Answer:

92gm

Explanation:

Atomic mass of Mg=24g=1 mole of Mg

∴ 24g =1 mole of Mg contain 6.022×10^23 atom

∴ 6gm contains 246.022×1023×6

=4×6.022×10^23 atoms

Now according to question, there are 6.022×1023 atoms of Na

23gm of Na contains 6.022×10^23 atoms

∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm

3 0

3 years ago

If the atomic number of an element is 6 and its mass number is 4 how many neutrons are contained in the nucleus? A. 14 B. 6 C. 8

leonid [27]

The answer is B. There are 6 neutrons

5 0

3 years ago

Name two methods of separating mixtures. Describe the property each of these separations based

grigory [225]

Answer:

Distillation and using Chromatography

Explanation:

Distillation:

based on using boiling point.

Ex: separating a mixture of water and sugar by boiling the water away.

Chromatography:

based on absorption

Ex: separating the different colours that make up a black marker

8 0

3 years ago