(67 + 68 + 78 + x) / 4 = 70
(213 + x) / 4 = 70
213 + x = 70 * 4
213 + x = 280
x = 280 - 213
x = 67

(213 + x) / 4 = 79
213 + x = 79 * 4
213 + x = 316
x = 316 - 213
x = 103

lowest u can make is 67, highest u can make is 100

4 0

3 years ago

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The perimeter of a rectangle is 20.2 CM and it's area is 24.4 cm squared what is its length and width

erma4kov [3.2K]

Answer:

Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm

Step-by-step explanation:

Given as :

The perimeter of rectangle = 20.2 cm

The area of rectangle is 24.4 cm

Let the length be L

And width be w

Now Area of rectangle = Length × width

Or, 24.4 = L × W

And Perimeter = 2 (Length + Width ) = 2 (L + W )

Or, 20.2 = 2(L + W )

Or , L + W = 10.1 cm ............ 1

Now, (L - W )² = (L + W)² -4 LW

Or, (L - W )² = ( 10.1)² -4 (24.4)

I.e (L - W )² = 4.41

Or , L - W = 2.1 cm .............. 2

SO , From 1 and 2

( L + W) + (L - W) = 10.1 cm - 2.1 cm

Or, 2L = 8

∴ Length = 4 cm

Again , Width = 4 cm - 2.1 cm = 1.9 cm

Hence Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm Answer

6 0

3 years ago

Find the first, fourth, and 10th terms of the arithmetic sequence described by the given rule.

mrs_skeptik [129]

$\bf \begin{array}{ll} \stackrel{term}{n}&\stackrel{-6+(n-1)\frac{1}{5}}{value}\\ \cline{1-2} 1&-6+(1-1)\frac{1}{5}\\ &-6+0\\[1em] &-6\\[1em] 4&-6+(4-1)\frac{1}{5}\\ &-6+\frac{3}{5}\\[1em] &\frac{-27}{5}\\[1em] 10&-6+(10-1)\frac{1}{5}\\ &-6+\frac{9}{5}\\[1em] &\frac{-21}{5} \end{array}$

4 0

3 years ago

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