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2 years ago

Find the volume of this figure. round your answer to the nearest hundredth. if necessary#8

Mathematics

1 answer:

ivann1987 [24]2 years ago

4 0

Answer:

30 miles²

Step-by-step explanation:

To solve the area of the prism we have to multiply the area of the base * the height of the prism. The base of the prism is a right triangle.

(b*h)÷2 = Area of a triangle

Base = 4

Height = 3

Now:

(4*3)/2 = 6 miles²

Now we have to multiply 6 miles² by 5 as our height.

We get 30 miles² as the volume of the figure.

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3−2x=2x+3(6−3x)−7(1−2y)=25+6y

Zielflug [23.3K]

Answer:

Step-by-step explanation:

First you need to use the distributive property:

3-2x+2x+3(6-3x)-7(1-2y)=25+6y

3-2x=2x+18-9x-7+14y=25+6y

3-2x=-7x+11+14y=25+6y

Then Split up the equations.

3-2x=-7x+11

Subtract 3 from both sides

-2x=-7x+8

Then add -7x to both sides

5x=8

Then divide both sides by 5x

X= $\frac{5}{8}$

To solve for y: just use 14y=25+6y

Subtract both sides by 6y

8y=25

Then divide both sides by 8y

y= $\frac{25}{8}$

7 0

3 years ago

Which number line represents the solution set for the inequality 3(8-4x) < 6(x - 5)?

STatiana [176]

Answer:

x>3

Step-by-step explanation:

We are given with the inequation 3(8-4x) < 6(x - 5)

Dividing both sides in the above in equation by 3 we get

(8-4x)<2(x-5)

Distributing 2 over (x-5)

(8-4x)<2x-10

8-4x<2x-10

adding 10 and 4x on both hand sides we get

8+10<2x+4x

18<6x

Dividing both sides by 6 we get

3<x

Hence the solution to the given in equation is x>3

7 0

3 years ago

Which algebraic expressions are polynomials? Check all that apply. PLEASE HELP

dexar [7]

Selections 2, 3, 5, 6 are polynomials.

1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).

3 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$