Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Answer:
To speed up the rate of reaction, you could increase the temperature or the concentration of the reactants.
Explanation:
Basically, the idea is to speed up the molecules' movement and to cause them to break apart or collide at greater frequency
Answer:
c. A to K
Explanation:
If the alanine mutation is restored to K or lysine residue, most likely the wild type level of activity can be restored. This is because, arginine and lysine have -NH2 as the functional group. So, functional similarity of arginine can be expected from lysine as well.
Hence the correct option is c that is A to K.
Answer:
Chemical. quimico
Explanation:
Hope this helps. Chemical, because it's being exposed, no one is exposing it.
Espero que esto ayude. Quimico, porque esta expuesto, nadie lo esta exponiendo.
se un poco de espanol
buena suerte
If I'm not mistaken, I believe the baby has a heart beat.