The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
brainly.com/question/13531044
Answer:
chemical, substance, different
Explanation:
This is what I would put... the question sounds rather open ended though. HTH :)
M. E. R. P.
I need to do this so sorry
The element that would melt at a higher temperature than the standard temperature is iron (Fe).
<h3>Melting point</h3>
The term melting point refers to the point where a solid is converted to a liquid. A pure substance has a sharp melting point while an impure substance melts over a temperature range.
Metals have a very high melting point hence the element that would melt at a higher temperature than the standard temperature is iron (Fe).
Missing parts:
At standard pressure, which element has a melting point higher than standard temperature?
(1) F2 (3) Fe
(2) Br2 (4) Hg
Learn more about melting point: brainly.com/question/491382