Answer:
10%
Step-by-step explanation:
The computation of the percentage of bulbs that switched on incandescent is as follows;
Let us assume the incandescent be I
And, the fluorescent be F
Now the equation is
0.4I + 0.9F = 0.8 (I+F)
0.41I + 0.9F = 0.8I + 0.8F
So here
0.4I = 0.1F
Now the percentage would be for incandescent in the case of switched on is
= 0.4I ÷ 0.8(I+F) × 100
= 0.1F ÷ 1F
= 10%
Answer:
ITS A B F ON EDGE GUYS THE PEOPLE IN COMMENTS RIGHT!!!!!1
For this case we have the following parent function:
f (x) = x ^ 2
We apply the following function transformation:
Horizontal translations
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
y = (x + 3) ^ 2
Vertical translations
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
We have then:
y = (x + 3) ^ 2 + 4
Answer:
The graph g (x) is the graph f (x) 3 units to the left and 4 units up:
y = (x + 3) ^ 2 + 4
