Answer:

Step-by-step explanation:

Use the distibutivve property to multiply -6 by 1.4 - r

Then move over 6r to the front

Considering it's vertical asymptote, the rational function graphed below is given by:
A.
.
<h3>What are the vertical asymptotes of a function f(x)?</h3>
The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
In this graph, there is a vertical asymptote at x = 4, that is, x - 4 is a term of the denominator, hence the function is given by:
A.
.
More can be learned about vertical asymptotes at brainly.com/question/16948935
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We have to set up 2 different equations if we are to solve for 2 unknowns. The first equation is x = y + 4. One number (x) is (=) 4 more than another (y + 4). Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger. The second equation then is

. In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation:

. Expand that binomial to get

. Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64. Solving for y we get that y = 6. Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!
Answer:
Step-by-step explanation:
Let X be the IQ
IQ is normally distributed with a mean of 100 and a standard deviation of 15.
a) the probability that this person has an IQ greater than 95
=
=62.93%
b) the probability that this person has an IQ less than 125

=4.75%
c) Sample size =500

No of people = 0.2486(500) =124.3
d) 
No of persons = 0.0047(500) = 2.35
Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft