All categories

3 years ago

What happens when the diaphragm is lowered?

Physics

1 answer:

Leto [7]3 years ago

6 0

The space in your chest cavity increases, so your lungs expand and are filled with air,

You might be interested in

Which is the quickest way to accurately take your heart rate

Thepotemich [5.8K]

I would say by putting two fingers under your chin or putting two fingers on the back of your wrist, hope i helped ! :)

3 0

3 years ago

If a cart of 10 kg mass has a force of 5 newtons exerted on it, what is its acceleration? m/s2

Elza [17]

Answer:

= 0.5 m/s²

Explanation:

According to Newton's second law of motion, the resultant force is directly proportion to the rate of change of linear momentum.

Therefore; F = ma , where F is the Force, m is the mass and a is the acceleration.

Thus; a = F/m

but; F = 5 N, and m = 10 kg

 a = 5 /10

= 0.5 m/s²

4 0

3 years ago

Read 2 more answers

5. The analytical method of adding vectors expressed in terms of their components may be applied to vectors in three dimensions,

Gwar [14]

Answer:

C = 17 i^ - 7 j^ + 16 k^ , | C| = 24.37

Explanation:

To work the vactor component method, we add the sum in each axis

C = A + B = (Aₓ + Bₓ) i ^ + ( $A_{y}$ + $B_{y}$ ) i ^ + ( $A_{z}$ + $B_{z}$ ) k ^

Cₓ = 12+ 5 = 17

$C_{y}$ = -37 +30 = -7

$C_{z}$ = 58 -42 = 16

Resulting vector

C = 17 i ^ - 7j ^ + 16k ^

The mangitude of the vector is

| C | = √ c²

| C | = √( 17² + 7² + 16²)

| C| = 24.37

6 0

3 years ago

50. The potential energy of a spring is 0.3 J when it is compressed 0.04 m to the left of its equilibrium

lozanna [386]

Answer:

Your answer should be A. 0.25 J and moving to the right

Explanation:

6 0

2 years ago

The photeselestric effect is observed when light of a sufficiently high frequency is focused onto a polished metal surface, emit

Helga [31]

Answer:

$3.4\cdot 10^{-19} J$

Explanation:

In order to convert the work function of cesium from electronvolts to Joules, we must use the following conversion factor:

$1 eV = 1.6 \cdot 10^{-19} J$

In our problem, the work function of cesium is

$E=2.1 eV$

so, we can convert it into Joules by using the following proportion:

$1 eV : 1.6\cdot 10^{-19} J = 2.1 eV : x\\x=\frac{(1.6\cdot 10^{-19} J)(2.1 eV)}{1 eV}=3.4\cdot 10^{-19} J$

8 0

3 years ago