Answer:
(A) ratio of electric force to weight will be 
(b) Electric field will be 
Explanation:
We have given mass of bee = 100 mg = 
Charge on bee 
Electric field E = 100 N/C
Weight of the bee 
Electric force on the bee 
So the ratio of electric force on the bee and weight is 
(B) To hold the bee in air electric force must be equal to weight of bee
So 


Answer:
3m/s²
Explanation:
final velocity - initial velocity
______________________ = Acceleration
elapsed time
The linear speed of the passengers in kilometres/hour is 1.152 km/h.
The centrifugal force ride spins at a speed of 22 rev/min. The diameter of the ride is 14 meters.
We know,
Diameter = 2(Radius)
Radius = 14/2m
Radius = 7m
Radius of the centrifugal ride is 7m.
Also,
1 rev = 2π radians
22 rev = 44π radian
Angular Speed in rad/s = 44π/60
The relationship between the angular speed W and the linear speed V is given as,
V = W/R
R is the radius of the circle,
Now, putting the values,
V = 44π/(60×7)
V = 0.32 m/s.
So, the linear speed of the passengers is 0.32 m/s.
It is know, for conversion from m/s to km/h
1 m/s = 3600/1000 km/h
So, 0.32m/s in km/h is,
0.32m/s = 0.32 × 3600/1000
Linear speed in km/h is 1.152km/h.
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Answer:
G.P.E = 368.3
Explanation:
Given the following data;
Mass = 2.63kg
Height, h = 14.29m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;

Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.

G.P.E = 368.3
Note: the unit of gravitational potential energy is Joules.
A because it doesn't have properties of transverse waves or longitudinal.