A tree is leaning at a 5° angle from vertical, making an 85° angle with the ground. when the sun is at a 65° angle of elevation,
1 answer:
using the law of sines, the approximate length of the tree is calculated as: C. 45 ft.
<h3>What is the Law of Sines?</h3>The law of sines is given as: sin A/a = sin B/b = sin C/c, which is used to solve a triangle.
Given the following:
- H = the length of the tree = ? (b)
- Let sin A = 30°
- a = 25
- Sin B = 65°
Apply the law of sines
sin 30/25 = sin 65/H
H = (sin 65 × 25)/sin 30
H ≈ 45 ft.
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Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
~15 meters away
Step-by-step explanation:
c^2 = a^2+b^2
c^2 = 10^2+11^2
c^2 = 100+121
c^2 = 221
c =
c = ~15