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faust18 [17]
2 years ago
10

Setup a trig equation to solve for the angle indicated:

Mathematics
1 answer:
Mandarinka [93]2 years ago
6 0

Answer:

\cos(θ)  =  \frac{4}{5}

is the trig equation

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Consider a triangle with two sides that
AURORKA [14]

9514 1404 393

Answer:

  C)  14 cm

Step-by-step explanation:

A triangle solver can quickly show you the third side is 14 cm.

__

The law of cosines can be used for this purpose. If the given sides are 'a' and 'b', and the third side is 'c', then that law tells you ...

  c² = a² +b² -2ab·cos(C)

  c² = 7² +11² -2·7·11·cos(100°) ≈ 196.74

  c ≈ √196.74 ≈ 14.03

The length of the third side is about 14 cm.

8 0
3 years ago
What are these two questions please help
Kay [80]
15 feet is what I came up with.

3 0
3 years ago
4 1/2 + 1 + 2 + 1 1/2 + 4 + 1/2
mafiozo [28]
Your answer would be 17 1/2
7 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
If p(x) = 3x – 2and n (x) = 2x – 5, what is the value of (n/p) (1)?
Liula [17]

Answer:

-3

Step-by-step explanation:

We want (n/p)(1).  We can obtain this by finding n(1) and p(1) and then dividing as indicated:

p(1) = 3(1) - 2 = 1

n(1) = 2(1) - 5 = -3

Then   (n/p) (1) = -3/1, or just -3

5 0
2 years ago
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