Answer:
x=1.5
Step-by-step explanation:
Answer:
Answer is 
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.



Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
-4x + 7y = 9 ⇒ -4x + 7y = 9 ⇒ 8x - 14y = -18
2y = -5x - 22 ⇒ -5x - 2y = 22 ⇒ <u>-35x - 14y = 154</u>
<u>43x</u> = <u>-172</u>
43 43
x = -4
-4x + 7y = 9
-4(-4) + 7y = 9
16 + 7y = 9
<u>- 16 - 16</u>
<u>7y</u> = <u>-7</u>
7 7
y = -1
(x, y) = (-4, -1)
Distribute the 12 by multiplying so it would be 96b-60 and they aren’t like terms so that’s as far as you can go