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Dvinal [7]
4 years ago
15

Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe

r, B, has a volume of 117 mL. A sample of gas originally in container A is at 22.5 C and the pressure is 165 mmHg. What is the pressure (in mmHg) of the gas sample when the valve is opened and the gas now occupies both containers at a temperature of 12.7 C
Chemistry
1 answer:
stiv31 [10]4 years ago
8 0

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in container A = 165 mmHg

P_2 = final pressure of gas = ?

V_1 = initial volume of gas in container A= 135 mL

V_2 = final volume of gas = 135 mL + 117 mL = 252 mL

T_1 = initial temperature of gas in container A = 22.5^oC=273+22.5=295.5 K

T_2 = final temperature of gas = 12.7^oC=273+12.7=285.7K

Now put all the given values in the above equation, we get:

P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}

=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}

P_2=85.5 mmHg

85.5 mmHg is the pressure of the gas sample when the valve is opened.

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