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3 years ago

What is evidence of a physical change. A.ice melts B.silver tarnishes C.biycicle rusts

Chemistry

1 answer:

timama [110]3 years ago

3 0

C. Physical Change.

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A mixture of gases at a total pressure of 95 kPa contains N₂, CO₂, and O₂. The partial pressure of the CO₂ is 24 kPa and the par

Zinaida [17]

Answer:

23 kPa = Partial pressure O₂

Explanation:

In a mixture of gases, the sum of partial pressure of each gas that contains the mixture = Total pressure

Total pressure = Partial pressure N₂ + Partial pressure CO₂ + Partial pressure O₂

95 kPa = 48 kPa + 24 kPa + Partial pressure O₂

95 kPa - 48 kPa - 24 kPa = Partial pressure O₂

23 kPa = Partial pressure O₂

7 0

3 years ago

Please help me with this. (: I'd appreciate it.

Soloha48 [4]

Answer:

The answer to your question is: ΔH = -283 kJ/mol, first option

Explanation:

Reaction

CO + O₂ ⇒ CO₂

ΔH = ∑H products - ∑H products

ΔH = -393.5 - (-110.5 + 0)

ΔH = -393.5 + 110.5

ΔH = -283 kJ/mol

4 0

3 years ago

Select which of the following are used to determine the age of the Earth. Select 3.

saveliy_v [14]

Meteorites discovered on earth

7 0

2 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

3 years ago

A distance of one centimeter is the same as ?

rodikova [14]

C because its meters right

4 0

3 years ago