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Mkey [24]
3 years ago
10

Pb is a line segment on a number line. It has endpoints at -2 and 12. What is the coordinate of its midpoint

Mathematics
1 answer:
kiruha [24]3 years ago
8 0
5 because if you draw the line segment out the middle will be 5
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The perimeter of a rectangular park is 2.6 miles. the length of the park is 0.8 miles. what is the width of the park
mr_godi [17]
The answer is 0.5 miles
8 0
3 years ago
A simple random sample of size nequals15 is drawn from a population that is normally distributed. The sample mean is found to be
Bond [772]

Answer with explanation:

To test the Significance of the population which is Normally Distributed we will use the following Formula Called Z test

   z=\frac{\Bar X - \mu}{\frac{\sigma}{n}}

\Bar X =31.1\\\\ \sigma=6.3\\\\ \mu=25\\\\n=15\\\\z=\frac{31.1-25}{\frac{6.3}{\sqrt{15}}}\\\\z=\frac{6.1\times\sqrt{15}}{6.3}\\\\z=\frac{6.1 \times 3.88}{6.3}\\\\z=3.756

→p(Probability) Value when ,z=3.756 is equal to= 0.99992=0.9999

⇒Significance Level (α)=0.01

We will do Hypothesis testing to check whether population mean is different from 25 at the alpha equals 0.01 level of significance.

→0.9999 > 0.01

→p value > α

With a z value of 3.75, it is only 3.75% chance that ,mean will be different from 25.

So,we conclude that results are not significant.So,at 0.01 level of significance population mean will not be different from 25.

3 0
3 years ago
Members of the band are selling candy bars to raise money. The director uses this equation to calculate the amount of profit, p,
ivolga24 [154]

Answer:

<h3>C. 800</h3>

Step-by-step explanation:

Given the equation used to calculate the amount of profit, p, made from selling n candy bars expressed as  p = 1.50n – 500

To find the number of candies sold for $700, we are going to substitute p = $700 into the given expression and find n as shown;

700 =  1.50n - 500

Add 500 to both sides

700+500 = 1.50n-500+500

1200 = 1.50n

Divide both sides by 1.50

1200/1.50 = 1.50n/1.50

800 = n

Rearrange

n = 800

Hence 800 candy bars must be sold to make $700 profit

7 0
2 years ago
Suppose in this semester, our Exam 1 average was about 86 with an SD of about 10. Suppose the correlation between our Exam 1 and
Oduvanchick [21]

Answer:

the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

Step-by-step explanation:

Given the data in the question;  

mean X" = 86

SD σx = 10

Y" = 76

SD σy = 8.2

r = 0.6

Here, Exam 2 is dependent and Exam 1 is independent.

The Regression equation is

y - Y" = r × σy/σx  ( x - x" )

we substitute

y - 76 = 0.6 × 8.2/10  ( x - 86 )

y  - 76 = 0.492( x - 86 )

y  - 76 = 0.492x - 42.312

y = 0.492x - 42.312 + 76

y = 0.492x + 33.688

Hence, the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

4 0
3 years ago
Please help, I’m new to this app so O
umka2103 [35]

Answer:

x=10 5x=50 2x=20

Step-by-step explanation:

5x+2x+110=180

180-110=70

7x=70

x=10

5*10=50

2*10=20

5 0
3 years ago
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