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Mkey [24]
2 years ago
10

Pb is a line segment on a number line. It has endpoints at -2 and 12. What is the coordinate of its midpoint

Mathematics
1 answer:
kiruha [24]2 years ago
8 0
5 because if you draw the line segment out the middle will be 5
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Question 6 (Essay Worth 5 points) Part A: Find a rational number that is between 5.2 and 5.5. Explain why it is rational. (2 poi
insens350 [35]
Rational between 5.2 and 5.5

5.2 × 10/10 = 52/10
5.5 × 10/10 = 55/10
rational no. b/w them is 53/10 = 5.3

rational because it is in p/q form where q is not zero and p and q are integers.



irrational.no. b/w 5.2 and 5.5


5.20102030405060708090.......

irrational.no because it is non terminating and non recurring
6 0
3 years ago
Problemas de razonamiento división de números decimales. Ayer Susana se fue de viaje a visitar a unos familiares. Recorrió 135,7
schepotkina [342]

Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.

--------------------------

La <u>velocidad </u><u>es la distancia dividida por el tiempo</u>, por lo que:

v = \frac{d}{t}

  • Total de 135,75 km, o sea, d = 135,75
  • Llego en 1,5 horas, o sea, t = 1,5

La velocidad es:

v = \frac{d}{t} = \frac{135,75}{1,5}

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

v = \frac{135,75}{1,5} = \frac{1357,5}{15} = \frac{13575}{150} = 90,5

Ella condujo a una velocidad media de 90,5 km/h.

Un problema similar es dado en brainly.com/question/24558377

4 0
1 year ago
What is the area of the trapezoid that is not drawn to scale??
netineya [11]
I think the answer would be 38in^2

Because the equation is : (a+b) *h / 2
A and b are both the bases of the trapezium

So (11 + 8) these are the bases and the height is 4 so you would do
(11+8)*4 / 2
(19)*4 / 2
76 / 2
= 38
3 0
3 years ago
Read 2 more answers
Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
5 0
2 years ago
Jill says he did it wrong. He should have multiplied the bottom first (3 x 5) and then multiplied by the height. Explain to Jill
inna [77]

Answer:

Step-by-step explanation:

Jack's method is equivalent because of the "law of commutative property", which means that multiplication problems have the same result no matter the order.

2x5 is the same as 5x2

8 0
3 years ago
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