Answer:
Olha,pirmieiro voce adiciona o AAS com o AABC e depois divide por 2. depois, voce ai ter que simplificar. eu iria simplificar por 2 mas vcque sabe.
Step-by-step explanation:
9 x 0.55 = 4.95, which can be rounded to the ones place.
5 books remain.
Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
There is a theorem that says that, two tangent lines onto a circle that start from the same point are equal. For example, if we were to label the polygon ABCD, the tangent lines going from point A are equal, the lines going from point B are equal, etc.
Since we now know this rule, we can see that, for each point of the polygon you are given 1 out of 2 tangent lines for that point. Using this theorem, we can say that the other tangent line is equal to the first.
So, the bottom two tangents are 98 and 98, the right-side are both 22 and 22, the top are both 27 and 27, and the left are 22 and 22. We need to find the perimeter, or the sum of all the sides of the polygon. Seeing as the sides of the polygon are formed by all the tangent lines, we just have to find the sum of all the tangent lines.
98 + 98 + 22 + 22 + 27 + 27 + 22 + 22 =
= 196 + 88 + 54 (or 2*98 + 4*22 + 2+27) =
= 338 inches
I hope this wasnt too confusing.
Answer:
B.
R (2,4)
soln
center(h,k)=(6,1)
radius (r)=5units
so
eqn of circle is (x-6)^2+(y-1)^2=5^2
2 2
or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle