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3 years ago

10

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig

ht and the high and low temperature during the day are 64 and 26 degrees, respectively. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.\

1 answer:

Nady [450]3 years ago

5 0

Answer:

$D = 45+19*sin(\frac{\pi}{12}*t)$

Step-by-step explanation:

The amplitude (A) and the mean (M) temperature are given by:

$A=\frac{64-26}{2}\\ A= 19\\M=\frac{64+26}{2}\\ M= 45\\$

The mean temperature, 45 degrees. occurs at midnight (t=0) and the frequency is f=24h. Therefore, the temperature D, in degrees, as a function of t, in hours, is:

$D = M+A*sin(\frac{2\pi}{24}*t)\\D = 45+19*sin(\frac{\pi}{12}*t)$

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A survey was taken among a group of people. The probability that a person chosen likes Italian food is 0.75, the probability tha

Luda [366]

Answer:

54% probability that a person likes Italian food, but not Chinese food.

82% probaility that a person likes at least one of these foods

79% proability that a person likes at most one of these foods

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a person likes Italian food.

B is the probability that a person likes Chinese food.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a person likes Italian food but not Chinese and $A \cap B$ is the probability that a person likes both Italian and Chinese food.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that a person likes both foods is 0.21.

This means that $A \cap B = 0.21$

The probability that a person likes Chinese food is 0.28

This means that $B = 0.28$

So

$B = b + (A \cap B)$

$0.28 = b + 0.21$

$b = 0.07$

The probability that a person likes Italian food is 0.75

This means that $A = 0.75$

So

$A = a + (A \cap B)$

$0.75 = a + 0.21$

$a = 0.54$

Determine the probability that a person likes Italian, but not Chinese

This is a.

54% probability that a person likes Italian food, but not Chinese food.

Determine the probaility that a person likes at least one of these foods

$P = a + b + (A \cap B) = 0.54 + 0.07 + 0.21 = 0.82$

82% probaility that a person likes at least one of these foods

Determine the proability that a person likes at most one of these foods

Either a person likes at most one of these foods, or it likes both. The sum of the probabilities of these events is decimal 1.

0.21 probability it likes both.

Then

0.21 + p = 1

p = 0.79

79% proability that a person likes at most one of these foods

6 0

3 years ago

The sum of four consecutive odd integers is 216.find the four integer.

Alexus [3.1K]

The four consecutive odd integers are x, x+2, x+4, x+6
x+x+2+x+4+x+6=216
4x+12=216
4x=204
x=51
they are 51, 53, 55, 57

4 0

3 years ago

Read 2 more answers

The automatic opening device of a military cargo parachute has been designed to open when the parachute is 135 m above the groun

laiz [17]

Answer:

the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215

Step-by-step explanation:

Let consider Q to be the opening altitude.

The mean μ = 135 m

The standard deviation = 35 m

The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:

$P(Q$

$P(Q$

$P(Q$

$P(Q$

If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.

The probability of success = 0.1587

the number of independent parachute n = 5

the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:

P(R ≥ 1) = 1 - P(R < 1)

P(R ≥ 1) = 1 - P(R = 0)

The probability mass function of the binomial expression is:

P(R ≥ 1) = $1 - (^5_0)(0.1587)^0(1-0.1587)^{5-0}$

P(R ≥ 1) = $1 - (\dfrac{5!}{(5-0)!})(0.1587)^0(1-0.1587)^{5-0}$

P(R ≥ 1) = 1 - 0.5785

P(R ≥ 1) = 0.4215

Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215

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3 years ago

can someone help me to solve the first problem only please I will mark you the brainly helpful answers pls!

swat32

Answer:

When 2 lines are parallel, the sum of interior corresponding angles = 180

120 + b = 180

b = 180 - 120 = 60

a + 30 = 180

a = 180 - 30 = 150

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3 years ago

There are 4 cookies if there is 1/4 of a cookie in each bag how many bags will there be

Darya [45]

Answer:

there will be 16 bags

Step-by-step explanation:

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3 years ago