1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
TEA [102]
2 years ago
6

On Monday a team of street sweepers cleaned 1 1/3 city blocks. Tuesday, the team cleaned 1/5 as many blocks as on Monday. How ma

ny city blocks did the street sweepers clean on Tuesday?
Mathematics
1 answer:
valentina_108 [34]2 years ago
4 0

Answer: 4/15

Step-by-step explanation:
1. Change 1/3 to 4/3 by multiplying the numerator by 3 and adding one.

2. Multiple 4/3 by 1/5 to get 4/15.

You might be interested in
PLEASE PLEASE HELP!!!
natka813 [3]

Answer:

398,765 books were sold

Step-by-step explanation:

How to get the answer:

1) Identify the given

  32,300 is percentage

  8.1 % is rate

  base (b) is missing

2) Solve

   b= p/r

   b= 32,300 / 8.1% or 0.081

   b= 398,765

3) Check

   398,765 x 8.1% = 32,299.97 or 32,300

5 0
3 years ago
Two problems here I need solved! I need every step, so please have that with your answers!!
Free_Kalibri [48]
QUESTION 1

We want to solve,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}

We factor the denominator of the fraction on the right hand side to get,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.

This implies
\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}

We multiply through by LCM of
(x-4)(x - 2)

(x - 2) + x(x-4) = 2

We expand to get,

x - 2 + {x}^{2} - 4x= 2

We group like terms and equate everything to zero,

{x}^{2} + x - 4x - 2 - 2 = 0

We split the middle term,

{x}^{2} + - 3x - 4 = 0

We factor to get,

{x}^{2} + x - 4x- 4 = 0

x(x + 1) - 4(x + 1) = 0

(x + 1)(x - 4) = 0

x + 1 = 0 \: or \: x - 4 = 0

x = - 1 \: or \: x = 4

But
x = 4
is not in the domain of the given equation.

It is an extraneous solution.

\therefore \: x = - 1
is the only solution.

QUESTION 2

\sqrt{x+11} -x=-1

We add x to both sides,

\sqrt{x+11} =x-1

We square both sides,

x + 11 = (x - 1)^{2}

We expand to get,

x + 11 = {x}^{2} - 2x + 1

This implies,

{x}^{2} - 3x - 10 = 0

We solve this quadratic equation by factorization,

{x}^{2} - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x + 2)(x - 5) = 0

x + 2 = 0 \: or \: x - 5 = 0

x = - 2 \: or \: x = 5

But
x = - 2
is an extraneous solution

\therefore \: x = 5
7 0
3 years ago
PLEASE HELP ME WITH THIS​
Mice21 [21]
Wha do u need help with
8 0
3 years ago
7g + 11 subtracted from 12
BlackZzzverrR [31]
A subtracted from b means b-a

7g+11 subtracted from 12 means 12-(7g+11)=12-1(7g+11)=12-7g-11=12-11-7g=1-7g
5 0
3 years ago
HCF of smallest 2 digit composite number and smallest 3 digit prime number is?​
posledela

Answer:

HCF = 1

Step-by-step explanation:

Smallest 2 digit composite number = 10

Smallest  3 digit prime number = 101

Factors of 10 = 1 , 2 , 5

Factors of 101 = 1 , 101

HCF = 1

6 0
2 years ago
Other questions:
  • Evaluate.<br> [120 + (12 ÷ 3 • 30)] ÷ 20 + 102
    11·2 answers
  • A forest has 800800800 pine trees, but a disease is introduced that kills \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, e
    5·1 answer
  • Un tanque de almacenamiento de agua instalado en una comunidad tiene forma de prisma rectangular y una capacidad de 8 000 litros
    10·1 answer
  • PLEASE HELP ME!!!
    12·2 answers
  • Does anyone know the area?
    13·2 answers
  • 5. What is the value of x?
    8·1 answer
  • Which equation is represented by the line
    9·1 answer
  • (3) Lines that forms straight angles​
    7·1 answer
  • If the statements p,q are true statements and r,s are false statements then determine the truth value of the following.
    13·1 answer
  • Debbie has at most $60 to spend on clothes. She wants to buy a pair of jeans that cost $22 and spend the rest on t-shirts. Each
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!