Answer:
C. ± 2.326 years.
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so ![z = 2.326/tex]Now, find the width of the interval[tex]W = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%3D%202.326%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3ENow%3C%2Fstrong%3E%2C%20find%20the%20width%20of%20the%20interval%3C%2Fp%3E%3Cp%3E%5Btex%5DW%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which 
is the standard deviation of the population and n is the size of the sample.
In this question:
So
The correct answer is:
C. ± 2.326 years.
Answer:
um
Step-by-step explanation:
ok?
9514 1404 393
Answer:
245 cm²
Step-by-step explanation:
The surface area of a cone is given by ...
SA = πr(r +s) . . . . where r is the radius, and s is the slant height
Filling in the given values, we have ...
SA = (3.14)(3 cm)(3 cm +23 cm) = (3.14)(3)(26) cm² ≈ 245 cm²
The surface area of the cone is about 245 cm².
Answer:
63.9
Step-by-step explanation:
Convert 9% to a decimal: 0.09
710×.09=63.9
Please give me brainliest
8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things
