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Evgen [1.6K]
3 years ago
10

Como se halla la distancia entre AP?

Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

Huh! What does that means?

Step-by-step explanation:

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A minute hand on a clock made a 1/4 turn how many degrees did the minute hand turn
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So a going a whole circle around is 180  so if it goes 1/4 of it, it will be 720 
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What can be concluded about a sorting algorithm (such as insertion) that performs only adjacent interchanges??
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It is the most critical part in algorithm. This is to sort or arrange things or numbers in specific characteristics. This is to make things easier when you will be calculating and you can differentiate the results and your variable being considered in solving the problem.
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When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 63 seconds and a standard devia
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Answer: in 95% of races, his finishing time will be between 62 and 64 seconds.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 63 seconds and the standard deviation is 5 seconds.

2 standard deviations = 2 × 0.5 = 1

63 - 1 = 62 seconds

63 + 1 = 64 seconds

Therefore, in 95% of races, his finishing time will be between 62 and 64 seconds.

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Write seven hundred two and six hundred fifty-six thousandths in standard form and in expanded form.
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A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes
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Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

<u>Step-by-step explanation:</u>

1)         First       and        Second         and         Third

  \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}

2)         First       and          Second

   \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}

3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}

4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}

8 0
3 years ago
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