The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
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Answer:
<u>If you put a red blood cell in distilled water (100% H2O), there will be a net movement of water </u><u>from a region of higher concentration (100%) to a region of lower concentration </u><u>(the cell with 99.15% H2O). The distilled water outside the red blood cell, since it is 100% water and no salt, is hypotonic (it contains less salt than the red blood cell) to the red blood cell. The red blood cell will gain water, swell ad then burst. The bursting of the red blood cell is called hemolysis.</u>
Explanation:
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Answer:
Mass is the amount of matter in a substance is the correct answer
Difference of two squares
it always results in a^2-b^2
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