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Leni [432]
3 years ago
14

HEY PLEASE HELP I AM STRUGGLING!!

Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:


Step-by-step explanation:

ok the first box is linear

the 2nd isnt

the 3rd isnt either

the fourth is

not sure about 5th but im sure it isnt

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10 times as much as________is 1/10 of 900
Kruka [31]
The correct answer to this question is 9. This can be worked out due to the fact that 1/10 of 900 is 90, so to reach 90 you have to times 9 by 10.
5 0
2 years ago
MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE reposting cause no one answered them
sveta [45]

A

since the 3 is outside the radical then \sqrt{9} = 3, hence

x = 9

B

using the law of radicals

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we can separate the factors as

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C

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D

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6 0
3 years ago
In how many ways can a committee of 4 be chosen from a group of 9 people?
QveST [7]
Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.

C=n!/(k!(n-k)!)  where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices.  In this case:

C=9!/(4!(9-4)!)

C=9!/(4!5!)

C=362880/(24*120)

C=362880/2880

C=126

So there are 126 unique ways to pick 4 people from a group of 9 people.
3 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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