f(5) = 3 means (5,3) is on the graph of f.
On the new graph, y = f(x+1) + 2, what do the +1 and +2 do?
Things inside the function notation inpact the x-values, since that's where x sits.
This outside the f(x) notation impact the y-values, since those are done after you've evaluated the function.
"+1" on the inside shifts every point to the left 1 unit. (Inside changes are almost always opposite from what it looks like it would do.)
"+2" on the outside will shift every point up by 2 units.
So what do you get if you take (5,3) and shift it left 1 and up 2?
Answer:
I think you need the amount of boy children to solve this.
Answer:
x = 4
Step-by-step explanation:
-3x + 2 = -10x + 30
Add 10x to both sides and you get
7x + 2 = 30
Subtract 2 from both sides and you get
7x = 28
Divide both sides by 7 to get x by itself and you get
x = 4
Reminder whatever you do to one side you have to do to the other side!
Hope this helps!
Answer:
Answer:
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
Potatoes : No Potatoes : Difference Difference (d)²
(Potatoes- No Potatoes)
29 41 -12 144
25 41 -16 256
17 37 -20 400
36 29 -7 49
41 30 11 121
25 38 -13 169
32 39 -7 49
29 10 19 361
38 29 9 81
34 55 -21 441
24 29 -5 25
27 27 0 0
<u>29 31 -2 4 </u>
<u> ∑ -64 2100 </u>
- We state our null and alternative hypotheses as
H0 : μd= 0 and Ha: μd≠0
2. The significance level alpha is set at α = 0.01
3. The test statistic under H0 is
t= d`/sd/√n
which has t distribution with n-1 degrees of freedom.
4. The critical region is t > t (0.005,12) = 3.055
5. Computations
d`= ∑d/n = -64/ 13= -4.923
sd²= ∑(di-d`)²/ n-1 = 1/n01 [ ∑di² - (∑di)²/n]
= 1/12 [2100- ( -4.923)] = 175.410
sd= √175.410 = 13.244
t = d`/sd/√n= - 4.923/13.244/√13
t= - 4.923/3.67344
t= -1.340
6. Conclusion :
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
It is false!!! 8 1/2 is a mixed number!! when they have a whole number in front of it such as 8, or etc. and also. fraction... it's. mixed fraction! an improper fraction is like 57/4!! a big number over a smaller number!
