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Tomtit [17]
2 years ago
5

Express 1 − tan ⁡ θ sin ⁡ θ cos ⁡ θ in terms of cos ⁡ θ .

Mathematics
2 answers:
allsm [11]2 years ago
8 0

Answer:

cos^2(theta)

choli [55]2 years ago
5 0

1- \tan \theta \sin \theta \cos \theta \\\\=1- \dfrac{\sin \theta}{\cos \theta} \cdot \sin \theta \cdot \cos \theta\\\\=1-\sin^2 \theta \\\\=\cos^2 \theta

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Which could be the entire interval over which the function,
Marrrta [24]

Answer:

(-2, 1)

Step-by-step explanation:

Hi Juliadayx! How are you?

Well, maybe you already heard about the domain and the range of a function.  

The domain is the set of values that the independent variable can take (usually referred to as the letter "x"), while the range is the set of values that the dependent variable takes, which is called f(x) or function of x.

In this case, the exercise asks you to evaluate for which values of “x” (right column of the table), the function “f(x)” takes positive values (left column of the table), the positive values also include zero. And in this case you can see that the function f(x) is only positive for the values of "x": -2, -1, 0 and 1. Therefore, the answer is the entire interval (-2, 1).

I hope I've been helpful!

Regards!

3 0
3 years ago
Complete the steps to solve the inequality:<br><br> 0.2(x + 20) – 3 &gt; –7 – 6.2x
Zigmanuir [339]

answer: x > - 1.25

Step-by-step explanation:

0.2 •(x + 20)- 3> -7- 6.2x

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3 0
3 years ago
A hiking club has 9 members. How many ways can they choose a president, vice president, secretary, and treasurer from among the
nydimaria [60]
the\ variation\  without\  repetition:\\\\P(n;k)= \frac{\big{n!}}{\big{(n-k)!}} \\\\---------------------\\\\n=9\ \ \ and\ \ \ k=5\\\\\Rightarrow\ \ \ P(9;5)=\frac{\big{9!}}{\big{5!}}=\frac{\big{5!\cdot6\cdot7\cdot8\cdot9}}{\big{5!}}=3024\\\\Ans.\ there\ are\ 3024\ ways\ to\ choose.
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4 years ago
DEF is a dilation image of <br> ABC. What is the scale factor?
MrRa [10]
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5 0
3 years ago
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The sum of three consecutive odd integers is 87. Which equation could you use to find the three
Alexandra [31]

Answer:

k+(k+2)+(k+4)=87

The largest integer is 31.

Step-by-step explanation:

Hi there!

Let <em>k</em> be equal to the smallest of the integers.

Let (<em>k</em>+2) be the next odd integer.

Let (<em>k</em>+4) be the final odd integer.

We're given that the sum of these three integers is 87. Construct an equation:

k+(k+2)+(k+4)=87

Combine like terms:

k+k+2+k+4=87\\3k+6=87\\3k=81\\k=27

Therefore, the smallest integer is 27. Because the largest integer is k+4, the largest integer is therefore 31.

I hope this helps!

7 0
3 years ago
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