The answer is “B” because I just answered it
We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m
We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
1 mm³ = (10⁻³)³ m³
Therefore, the conversion used will be:
(1 mm / 10⁻³ m)³
When we multiply by this conversion, we will get:
32 m³ = 32 x 10⁹ mm³
Answer:
The fraction of the available octahedral positions are filled with
ions is 
Explanation:
If there are n numbers of spheres in HCP in packing:
Number of octahedral void = n
Number of tetrahedral void = 2n
Total number of voids = n + 2n = 3n
The
crystal structure consists of an HCP arrangement of
ions.
Number of spheres in HCP = 6
Number of
= 6
Number of octahedral voids = 6
Number of tetrahedral void = 12
Number of aluminum ions when there are 6
ion =
Number of voids in which
ions are present = 4
The fraction of the available octahedral positions are filled with
ions = 