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3 years ago

How do ionic bonds differ from covalent bonds? I NEED HELP QUICK PLSSS!!!!!

Chemistry

2 answers:

Norma-Jean [14]3 years ago

6 0

Answer:

Ionic bonds are usually between a metal and a nonmetal and involve the transfer of electrons. Covalent bonds are typically between two nonmetals and involve the sharing of electrons.

Explanation:

When elements bond together ionically, they transfer their valence electrons to another element to satisfy the octet rule and create full shells of 8 electrons. Metals usually have low electronegativity and ionization energy and can more easily give up an electron to a nonmetal with higher electronegativity and ionization energy.

When two nonmetals bond, their electronegativities are close enough in magnitude that neither element can "claim" the valence electrons, so the electrons orbit back and forth between the elements in the bond.

Brums [2.3K]3 years ago

4 0

Answer:

Explanation:

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Penicillinase, also known as β‑lactamase, is a bacterial enzyme that hydrolyzes and inactivates the antibiotic penicillin. Penic

sergeinik [125]

Explanation:

The given data is as follows.

$V_{max} = 6.8 \times 10^{-10} \mu mol/min$

$K_{m} = 5.2 \times 10^{-6} M$

Now, according to Michaelis-Menten kinetics,

$V_{o} = V_{max} \times [\frac{S}{(S + Km)}]$

where, S = substrate concentration = $10.4 \times 10^{-6}$ M

Now, putting the given values into the above formula as follows.

$V_{o} = V_{max} \times [\frac{S}{(S + Km)}]$

$V_{o} = 6.8 \times 10^{-10} \mu mol/min \times [\frac{10.4 \times 10^{-6} M}{(10.4 \times 10^{-6}M + 5.2 \times 10^{-6} M)}]$

$V_{o} = 6.8 \times 10^{-10} \mu mol/min \times 0.667$

= $4.5 \times 10^{-10} \mu mol/min$

This means that $V_{o}$ would approache $V_{max}$ .

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4 years ago

An inverse relationship can be represented by: a straight line a bar chart

kolezko [41]

Answer:

An inverse relationship can neither be represented by a straight line nor by a bar chart. But it can be represented by "xy = k"

Explanation:

Inverse relation is used for the values which are inversely related to each other. For example: Let suppose you have a value x and y. Then an increase in the value of x will result in the decrease of value y. Mathematically it is represented as,

x ∝ 1 / y

Where;

∝ = proportionality

Replacing the proportionality sign by a constant value "k" the relation becomes,

x = k / y

Solving for k,

x y = k

Conclusion:

Hence, an inverse relationship can be represented by "xy = k"

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3 years ago

Read 2 more answers

First to answer both CORRECTLY gets brainleist!

madam [21]

Answer: I am actually studying about Stars, so I got you.

3. As the temperature of a star Increases, it's luminosity increases.

As the temperature of a star decreases, it's luminosity decreases.

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3 years ago

Read 2 more answers

Hello, everyone!

marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the law of ideal gases,

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x $\frac{1 g}{1000 mg}$ x $\frac{1 mol}{28.01 g}$

→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V = $\frac{0.00125 mol x 0.082057 \frac{atm L}{mol K} x 243 K}{0.92 atm}$

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x $\frac{1000 cm^{3} }{1 L}$ = 27.09 cm³

Then the acceptable concentration c of CO in ppm is,

c = 27 cm³ / m³ = 27 ppm

To express this concentration in percent by volume we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 $\frac{cm^{3} }{m^{3} }$ x $\frac{1 m^{3} }{1 000 000 cm^{3} }$ x 100%

c = 0.003 %

So, the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is 27.09 ppm and 0.003 %.

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3 years ago

I 13 Suggest why this group is called Group 8.

yarga [219]

Answer:

because it's in group 8

Explanation:

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3 years ago