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pychu [463]
3 years ago
8

HELP Which of the following fractions can be used in the conversion of 32 m3 to the unit mm3?

Chemistry
1 answer:
poizon [28]3 years ago
7 0
We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m

We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
1 mm³ = (10⁻³)³ m³

Therefore, the conversion used will be:
(1 mm / 10⁻³ m)³

When we multiply by this conversion, we will get:
32 m³ = 32 x 10⁹ mm³
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8 0
3 years ago
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Lowering an object decrease is potential​
Tresset [83]

Answer:

Lowering the object near the ground decreases its <u>potential energy.</u>

<u></u>

Explanation:

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Example :

Change in shape and size :  When  you compress the spring , potential energy is introduced in it . So it expand quickly when you remove your hand.

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8 0
3 years ago
How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?
maw [93]
Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation
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3 years ago
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Goshia [24]

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3 years ago
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