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pychu [463]
3 years ago
8

HELP Which of the following fractions can be used in the conversion of 32 m3 to the unit mm3?

Chemistry
1 answer:
poizon [28]3 years ago
7 0
We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m

We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
1 mm³ = (10⁻³)³ m³

Therefore, the conversion used will be:
(1 mm / 10⁻³ m)³

When we multiply by this conversion, we will get:
32 m³ = 32 x 10⁹ mm³
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Calculate the ph of the solution made by adding 0.50 mol of hobr and 0.30 mol of kobr to 1.00 l of water. the value of ka for ho
nikdorinn [45]
To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:

Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr] 

HOBr  = 0.50 M 
KOBr  = 0.30 M = OBr-

<span>     HOBr + H2O <-> H+ + OBr- </span>
<span>I     0.50        -              0          0.30 </span>
<span>C       -x                        x             x 
</span>---------------------------------------------
<span>E(0.50-x)                    x       (0.30+x) </span>

<span>Assuming that the value of  x is small as compared to 0.30 and 0.50 </span>

<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>

<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
3 0
3 years ago
Which of the following molecules would you expect to have a dipole moment of zero?
Mashcka [7]

Answer:

CCl2=CCl2

Explanation:

Recall that the individual dipole moments in a symmetrical molecule cancel out each other thereby making the overall molecule to be non polar.

CCl2=CCl2 contain individual polar bonds but the molecule is highly symmetrical thus its dipole cancel out and the molecule has no overall dipole moment, hence CCl2=CCl2 has a dipole moment of zero .

6 0
3 years ago
Project 1 Hypothesis Construction
alukav5142 [94]

The hypothesis should be; "Increasing the amount of ice increases the rate at which the ice will melt"

<h3>What is a hypothesis?</h3>

The term hypothesis refers to a tentative explanation that could be applied in order to explain an observation. When we give a hypothesis, it must be subjected to rigorous experimentation thus it can be confirmed or repelled by experiment.

Now, we can see that the question here is; "How does the amount of salt added to ice affect the rate at which the ice will melt?" This implies that the correct hypothesis here ought to have to do with the impact of the amount of ice in the affirmative.

Thus, the hypothesis should be; "Increasing the amount of ice increases the rate at which the ice will melt"

Learn more about hypothesis:brainly.com/question/13025783

#SPJ1

5 0
1 year ago
Complete and balance the following symbol equation, and add state symbols
erastovalidia [21]

Answer:

2NaOH + H2So4 》Na2So4+ 2H2O

Explanation:

SODIUM HYDROXIDE, 2NaOH IS (aq)

FULFURIC ACID, H2So4 IS (aq)

SODIUM SULFATE, Na2So4 IS (aq)

WATER,2H20 IS (l)

5 0
3 years ago
Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là
BaLLatris [955]

<u>Answer:</u> The mass of FeO required is 14.37 g

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ......(1)

We are given:  

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol

The chemical equation for the reaction of FeO with sulfuric acid follows:

FeO+H_2SO_4\rightarrow FeSO_4+H_2O

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = \frac{1}{1}\times 0.200=0.200mol of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We know, molar mass of FeO = 71.84 g/mol

Putting values in above equation, we get:

\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g

Hence, the mass of FeO required is 14.37 g

4 0
3 years ago
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