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Natalka [10]
3 years ago
14

4 - 2(x-4)/ 3= 3(2x+5)/2pls answer fast​

Mathematics
1 answer:
adell [148]3 years ago
7 0

Answer:

-21/22

Step-by-step explanation:

1.Apply fraction cross multiply

2. Simplify

3.Expand

4.Subtract 24 from both sides

5.simplify

6. Subtract 18x form both sides

7.Simpiify, then divide both sides by -22to get answer.

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Step-by-step explanation:

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Answer:

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3 years ago
Big square length is 14 and small square length is 7. what is the area of dark part?
sladkih [1.3K]
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5 0
3 years ago
Find sec 2Theta in exact value
forsale [732]

Answer:

sec(2\theta)=-\frac{5}{4}

Step-by-step explanation:

we know that

step 1

Find cos(\theta)

we know that

tan^2(\theta)+1=sec^2(\theta)

we have

tan(\theta)=3

substitute

3^2+1=sec^2(\theta)

sec^2(\theta)=10

sec(\theta)=\pm\sqrt{10}

Remember that

Angle theta lie in Quadrant I

so

sec(\theta) is positive

sec(\theta)=\sqrt{10}

Remember that

sec(\theta)=\frac{1}{cos(\theta)}

therefore

cos(\theta)=\frac{1}{\sqrt{10}}

step 2

Find sin(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

sin(\theta)=tan(\theta)cos(\theta)

we have

cos(\theta)=\frac{1}{\sqrt{10}}

tan(\theta)=3

substitute

sin(\theta)=(3)(\frac{1}{\sqrt{10}})

sin(\theta)=\frac{3}{\sqrt{10}}

step 3

Find cos(2\theta)

we know that

cos(2\theta)=2cos^2(\theta)-1

we have

cos(\theta)=\frac{1}{\sqrt{10}}

substitute

cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1

cos(2\theta)=\frac{1}{5}-1

cos(2\theta)=-\frac{4}{5}

Remember that

sec(2\theta)=\frac{1}{cos(2\theta)}

therefore

sec(2\theta)=-\frac{5}{4}

8 0
3 years ago
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