Ask question

Ask question

All categories

2 years ago

11

I've been stuck on this assignment for 3 weeks now, help please.-Pics included-

1 answer:

Bond [772]2 years ago

3 0

1. 2NaN3 —> 2Na + 3N2
2. 2Pb + 2H2O + O2 —> 2Pb(OH)2
3. 2C4H12 + 13O2 —> 8CO2 + 10H2O
4. 4Fe + 3Sn(NO3)4 —> 4Fe(NO3)3 + 3Sn
5. Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3

Balancing equations depends on the atom numbers you start with.

If you are having trouble you can look up ‘chemical equation balancer’ and type in the starting elements and simply replace the arrow with an = equal sign and then enter the reactants. It will show you the balanced equation
But please— make sure you actually understand the process of balancing because it’s important for future chem classes

You might be interested in

a calorimeter contained 75.0 g of water at 16.95 C. A 93.3-g sample of iron at 65.58 C was placed in it, giving a final temperat

Nostrana [21]

Answer:- $\frac{382.69J}{0C}$ .

Solution:- Mass of Iron added to water is 93.3 g. Initial temperature of iron metal is 65.58 degree C and final temperature of the system is 19.68 degree C.

temperature change, $\Delta T$ for iron metal = 65.58 - 19.68 = 45.9 degree C

specific heat for the metal is given as 0.444 J per g per degree C.

let's calculate the heat lost by iron metal using the equation:

$q=mc\Delta T$

where, q is the heat energy, m is mass, c is specific heat and delta T is change in temperature. let's plug in the values and calculate q for iron metal:

$q=93.3g(45.9^0C)(\frac{0.444J}{g.^0C})$

q = 1901.42 J

Using same equation we will calculate the heat gained by water.

mass of water is 75.0 g.

$\Delta T$ for water = 19.68 - 16.95 = 2.73 degree C

specific heat for water is 4.184 J pr g per degree C. Let's plug in the values:

$q=75.0g(\frac{4.184J}{g.^0C})(2.73^0C)$

q = 856.674 J

Total heat lost by iron metal is the sum of heat gained by water and calorimeter.

So, heat gained by calorimeter = heat lost by iron metal - geat gained by water

heat gained by calorimeter = 1901.42 J - 856.674 J = 1044.746 J

Change in temperature for calrimeter is same as for water that is 2.73 degree C

For calorimeter, $q=C.\Delta T$

$C=\frac{q}{\Delta T}$

$C=\frac{1044.746J}{2.73^0C}$

$C=\frac{382.69J}{0C}$

So, the heat capacity of calorimeter is $\frac{382.69J}{0C}$ .

4 0

3 years ago

Balance the equation by inserting coefficients as needed. equation: C 2 H 6 O+O 2 longrightarrow CO 2 +H 2 O

shepuryov [24]

The coefficients needed to balance the equation would be 2, 7, 4, and 6 respectively.

<h3>Balancing chemical equation</h3>

This requires that the number of atoms of each element is the same both on the reactant and product's sides.

Hence, the balanced equation of the reaction becomes:

$2C_2 H_6 O+ 7O_2 --- > 4CO_2 +6H_2 O$

Thus, the coefficient for each species would be 2, 7, 4, and 6 respectively.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

4 0

3 years ago

The picture show multiple organisms called paramecia. Although paramecia (single-celled organisms) usually reproduce asexually,

agasfer [191]

Answer:

It means that the paramecium would be able to better control/regulate algae, bacteria, and other protists that can be found in water.

Explanation:

4 0

3 years ago

Read 2 more answers

What are 3 ways living creatures use carbohydrates

Zarrin [17]

Food, Storage, and Structure

4 0

3 years ago

Given the pH of 7. Explain how many hydroxide ions (-OH) and hydronium ions (H30+) are present in the solution.

irga5000 [103]

If the pH is 7, the solution is neutral, which means that it is an equal amount of acid and base.

6 0

3 years ago