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3 years ago

What physical effect can change the boiling point of a substance?

2 answers:

5 0

The correct answer for the following questions that are presented above are these ones:
(1) b. Pressure. The physical effect can change the boiling point of a substance is the pressure.
(2) Evaporation only occurs at the surface of a liquid. TRUE.
(3) d. freezing. The change from liquid to solid, or the reverse of melting, is called freezing.

Nesterboy [21]3 years ago

5 0

Answer 1:The correct answer is option b.

Explanation:

A boiling of the liquid is temperature at which the vapor pressure of the liquid becomes equal to the pressure exerted by the gas above it.

If the pressure of gas is 1 atm the liquid will boil at its normal boiling point.
If the pressure of the gas is less than that of the 1 atm than the liquid will boil at temperature lower than its normal boiling point.
If the pressure of the gas is more than 1 atm than the liquid will boil at temperature higher than its normal boiling point.

Evaporation is defined as surface process where water molecules from liquid state are converted into gaseous state from the surface of the liquid.

Answer 2:The correct answer is option d.

Explanation:

Freezing: It is a process in which liquid state of matter is converted into solid state of the matter.

Liquid state → Solid state

Condensation :The change of state of matter from gaseous state to liquid state is termed a condensation.

Boiling: It is a process by which a liquid is turned into a vapors by providing heat to the liquid.

Sublimation:The change of state of matter from solid state to gaseous state by escaping liquid state is termed a sublimation.

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A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to

Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure $P_{1}$ = 1.03 atm = 104.325 K pa

Initial temperature $T_{1}$ = 26 °c = 299 K

Initial volume $V_{1}$ = 22.4 L

Final temperature $T_{2}$ = 22 °c = 295 K

Final pressure $P_{2}$ = 0.81 atm = 82 K pa

We know that

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

Put all the values in above formula we get

$\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}$

$V_{2}$ = 28.11 L

This is the final volume of the balloon.

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