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irakobra [83]
3 years ago
11

What physical effect can change the boiling point of a substance?

Chemistry
2 answers:
AleksandrR [38]3 years ago
5 0
The correct answer for the following questions that are presented above are these ones:
(1) b. Pressure. The <span>physical effect can change the boiling point of a substance is the pressure.
(2) </span><span>Evaporation only occurs at the surface of a liquid. TRUE.</span><span>
(3) </span>d. freezing. The change from liquid to solid, or the reverse of melting, is called freezing.
Nesterboy [21]3 years ago
5 0

Answer 1:The correct answer is option b.

Explanation:

A boiling of the liquid is temperature at which the vapor pressure of the liquid becomes equal to the pressure exerted by the gas above it.

  • If the pressure of gas is 1 atm the liquid will boil at its normal boiling point.
  • If the pressure of the gas is less than that of the 1 atm than the liquid will boil at temperature lower than its normal boiling point.
  • If the pressure of the gas is more than 1 atm than the liquid will boil at temperature higher than its normal boiling point.

Evaporation is defined as surface process where water molecules from liquid state are converted into gaseous state from the surface of the liquid.

Answer 2:The correct answer is option d.

Explanation:

Freezing: It is a process in which liquid state of matter is converted into solid state of the matter.

Liquid state → Solid state

Condensation :The change of state of matter from gaseous state to liquid state is termed a condensation.

Boiling: It is a process by which a liquid is turned into a vapors by providing heat to the liquid.

Sublimation:The change of state of matter from solid state to gaseous state by escaping liquid state  is termed a sublimation.

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Read 2 more answers
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
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