the awnser is 30 hco because you have to add it because the numbers are too low to mutilply
Answer:
a) kc = 0,25
b) [A] = 0,41 M
c) [A] = <em>0,8 M</em>
[B] =<em>0,2 M</em>
[C] = <em>0,2M</em>
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.
If global reaction is:
A(g) + B(g) ⇋ 2 C(g) + D(s)
The kc = ![\frac{[C]^2}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5E2%7D%7B%5BA%5D%5BB%5D%7D)
a) The concentrations of each compound are:
[A] = 
= <em>0,4 M</em>
[B] = 
= <em>0,1 M</em>
[C] = = <em>0,1 M</em>
<em>kc = </em>![\frac{[0,1]^2}{[0,4][0,1]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C1%5D%5E2%7D%7B%5B0%2C4%5D%5B0%2C1%5D%7D)
= 0,25
b) The addition of B and D in the same amount will, in equilibrium, produce these changes:
[A] = 
[B] = 
[C] = 
0,25 = ![\frac{[0,60+2x]^2}{[1,60-x][0,60-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C60%2B2x%5D%5E2%7D%7B%5B1%2C60-x%5D%5B0%2C60-x%5D%7D)
You will obtain
3,75x² +2,95x +0,12 = 0
Solving
x =-0,74363479081119 → No physical sense
x =-0,043031875855476
Thus, concentration of A is:
= <em>0,41 M</em>
c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:
[A] = 
= <em>0,8 M</em>
[B] = 
= <em>0,2 M</em>
[C] = = <em>0,2M</em>
I hope it helps!
1. C
2. C
3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit.
4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust. Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress.
I hope this helped :D
1. Answer:
1.0 × 10–9 M OH–
Explanation:
pH = -Log[H+]
pOH = -Log[OH-]
But;
pH + pOH = 14
Therefore;
[H+] + [OH-] = 1.0 × 10^-14 M
Therefore;
[OH-] = 1.0 × 10^-14 M - (1.0 × 10^–5 M)
= 1.0 × 10^-9 M OH–
2. Answer;
pH = 7.28
Explanation;
pH = -Log[H3O+]
Given;
[H3O+] = 5.2 × 10^–8 M
Therefore;
pH = - log [5.2 × 10^–8 M]
= 7.28
The pH is 7.28
The answer is c because five plus two is seven and take away that is 4
