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kozerog [31]
2 years ago
7

How would speed change if the wave period increase

Physics
1 answer:
Valentin [98]2 years ago
6 0

Answer:

The greater the period the faster the wave moves (Figure 10.5).

Explanation:

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I need help with this today!!!
Veronika [31]


1. Rainbow (white light is split into its subsequent wavelengths)
2. Light enters through the cornea, is adjusted by the lens, the cones and rods of the retina are responsible for the perception of color and shadows, which are sent through the optic nerve to the occipital lobe of the brain.

3. Sound waves are intercepted by the pinna, travels through the auditory canal, reverberates on the eardrum, the vibrations travel through the ossicles of ear (hammer, anvil and stirrup), continuing to the cochlea and are sent through the auditory nerve to the brain.

4. A medium

5. Vibrations

6. All

7. Faster

8.Their kinetic energy increases

9. Conduction, convection and radiation

10. The heating of metals in the mantle, creates a current which slowly moves the plates above it.

5 0
4 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
Item 19 A student with arms outstretched stands on a platform that is rotating with a constant angular speed. The student then p
nadezda [96]

Answer:

An increase in angular speed due to conservation of energy priciple.

Explanation:

This leads to a decrease in your moment of inertia. This means that your angular velocity must increase as a result of conservation of energy principle and therefore you will spin faster.

It's also the same way this conservation of energy principle applies to ice skaters that makes them spin faster when they suddenly draw their arms inwards.

4 0
3 years ago
Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
JulsSmile [24]

Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

Final velocity v = 88 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

Time is given t = 12 sec

(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

a=2.0.37m/sec^2

So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

So 24.444^2=0^2+2\times 2.037\times s

s = 146.664 m

Distance traveled by the car in this interval will be 146.664 m

6 0
4 years ago
A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.
Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

    k x = m g

k = \dfrac{mg}{x}

k = \dfrac{6.4 \times 9.8}{0.28}

      k = 224 N/m

b) f = \dfrac{\omega}{2\pi}

    \omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}

  f =0.94\ Hz

c)  v_b = -v cos \omega t

    v_b = -5.1 \times cos (5.92 \times 0.42)

    v_b = 4.04\ m/s

d)  a_{max} = v \omega

    a_{max} = 4.04 \times 5.92

    a_{max} =23.94\ m/s^2

e)  Y =- A sin (\omega t)

    A = \dfrac{v}{\omega}

    A = \dfrac{4.04}{5.92}

        A = 0.682 m

    Y =- 0.682 \times sin (5.92 \times 0.42)

    Y =- 0.42

Force =m \omega^2 |Y|

          =6.4 \times 5.92^2\times 0.42

F = 94.20 N

4 0
4 years ago
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