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alina1380 [7]
4 years ago
10

Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe

s it go in this time?
Physics
1 answer:
JulsSmile [24]4 years ago
6 0

Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

Final velocity v = 88 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

Time is given t = 12 sec

(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

a=2.0.37m/sec^2

So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

So 24.444^2=0^2+2\times 2.037\times s

s = 146.664 m

Distance traveled by the car in this interval will be 146.664 m

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